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3 years ago

Help...is it Air??? Idk..

Chemistry

1 answer:

seraphim [82]3 years ago

5 0

Answer:

A. Air

Explanation:

Air is a very good thermal insulator.

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What state of matter is flubber is it a solid,liquid,or gos?

mafiozo [28]

Flubber would have to be a liquid, but it has characteristics which are impossible under the known laws of physics. I heard my teacher say that once

4 0

3 years ago

The wavelength of transmission is 9.7mm. What is the energy of this transition

Sonja [21]

Answer:

E = 2.05×10⁻²³ J

Explanation:

Given data:

Wavelength of transmission = 9.7 mm (9.7/1000 = 0.0097 m)

Energy of transition = ?

Solution:

9.7 mm (9.7/1000 = 0.0097 m)

9.7×10⁻³ m

Formula:

E = hc/λ

By putting values,

E = 6.63 ×10⁻³⁴ Js × 3×10⁸ m/s / 9.7×10⁻³ m

E = 19.89×10⁻²⁶ J.m / 9.7×10⁻³ m

E = 2.05×10⁻²³ J

3 0

3 years ago

Which of the following would dissolve in water? CCl4 LiCl CH4 PCl6

babymother [125]

Like dissolves like
so water is polar

CCl4 is nonpolar
LiCl is polar
CH4 is nonpolar
PCl6 is nonpolar

so LiCl would dissolve

7 0

3 years ago

Read 2 more answers

Which parts of sedimentary rock formation include the breakdown and carrying away of existing rock? Check all that apply.

stiks02 [169]

Answer

Weathering and erosion are two processes of which sedimentary rocks are broken down and carry away existing rocks.

Explanation:

3 0

3 years ago

What would be the freezing point of a solution that has a molality of 1.324 m which was prepared by dissolving biphenyl (C12H10)

lbvjy [14]

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.

$\Delta T = i \times Kf \times m = 1 \times 6.90 \°C/m \times 1.324m = 9.14 \°C$

where,

i: van 't Hoff factor (1 for non-electrolytes)
Kf: cryoscopic constant
m: molality

The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:

$T = 80.26 \° C - 9.14 \° C = 71.12 \° C$

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

Learn more: brainly.com/question/2292439

3 0

2 years ago