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Alex73 [517]
2 years ago
13

The length of a certain lot if 20 feet less than four times its width. the area of 4200 sq. ft. what are the dimensions of the l

ot?
Mathematics
1 answer:
tia_tia [17]2 years ago
3 0
The area of a surface is the number of square units present in the surface. For a rectangle, it is calculated from the product of the length and the width. To determine the length and width of the lot given above, we first assume that it is in a rectangular shape which is defined by its length and its width. We are given the following:

Area = 4200 square feet
Length = 4x - 20 feet
Width = x feet

From the definition of the area of a rectangle,

Area = length x width
4200 = (4x -20) (x)
4200 = 4x^2 - 20x
4x^2 - 20x - 4200 = 0
4(x^2 - 5x - 1050) = 0
x^2 - 5x -1050 = 0

Factoring the equation would lead to:
(x - 35) (x +30) = 0
x -35 = 0 ; x = 35
x + 30 = 0 ; x = -30

The width should not be a negative value so the width would be equal to 35 feet. So, the length would be 

Length = 4(35) - 20 = 120 feet

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Answer:

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Step-by-step explanation:

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The x-value that the line passes through here is the point x = -1 and that is the equation of the axis of symmetry

c) The vertex represents the lowest point of the circle here,

As we can see, this is the point through which the axis of symmetry passes through to make a symmetrical division of the parabola

We have the coordinates of this point as

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We have this point as 2 and -4

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2 years ago
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2 years ago
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3 years ago
What are the coordinates of point B?
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Midpoint is (2.5, 3.5) => (a,b)

Point B is (x2, y2)

To find midpoint we use formula

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Plug in all the values and findout x2, y2

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The point B is ( 7, 3)

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3 years ago
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