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Alex73 [517]
3 years ago
13

The length of a certain lot if 20 feet less than four times its width. the area of 4200 sq. ft. what are the dimensions of the l

ot?
Mathematics
1 answer:
tia_tia [17]3 years ago
3 0
The area of a surface is the number of square units present in the surface. For a rectangle, it is calculated from the product of the length and the width. To determine the length and width of the lot given above, we first assume that it is in a rectangular shape which is defined by its length and its width. We are given the following:

Area = 4200 square feet
Length = 4x - 20 feet
Width = x feet

From the definition of the area of a rectangle,

Area = length x width
4200 = (4x -20) (x)
4200 = 4x^2 - 20x
4x^2 - 20x - 4200 = 0
4(x^2 - 5x - 1050) = 0
x^2 - 5x -1050 = 0

Factoring the equation would lead to:
(x - 35) (x +30) = 0
x -35 = 0 ; x = 35
x + 30 = 0 ; x = -30

The width should not be a negative value so the width would be equal to 35 feet. So, the length would be 

Length = 4(35) - 20 = 120 feet

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The rate of change of the distance from the particle to the origin at this instant is 3 units per second.

<h3>What is the rate of change?</h3>

The instantaneous rate of change is the rate of change at a particular instant.

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<u>QUESTION 1</u>

The given system of equation is

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3x+2(x-6)=8


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5x-12=8


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5x=8+12

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We now substitute x=4 in to equation (1) to obtain,


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<u>QUESTION 2</u>

The given system of equations is

y-x=9...eqn1


and

10+2x=-2y...eqn2

We make y the subject in equation (2) to get,

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We put equation (3) into equation (1) to obtain,


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