Question

A toy projectile is fired vertically from the ground upward with a velocity of +29 meters per second. It arrives at its maximum altitude in 3.0 seconds. How high does the projectile go?

Answer 1

Answer:

$\boxed{\text{\sf \Large 42 m}}$

Explanation:

Use height formula

$\displaystyle \sf H=\frac{u^2 sin(\theta)^2}{2g}$

u is initial velocity

θ = 90° (fired vertically upward)

g is acceleration of gravity

$\displaystyle \sf H=\frac{29^2 \times sin(90 )^2}{2 \times 10}=42.05$