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UkoKoshka [18]
1 year ago
13

A grandfather clock depends on the period of a pendulum to keep correct time.(ii) Suppose a grandfather clock is calibrated corr

ectly at sea level and is then taken to the top of a very tall mountain. Does the grandfather clock now run (a) slow, (b) fast, or (c) correctly?
Physics
1 answer:
ANEK [815]1 year ago
6 0

The grandfather clock will now run slow (Option A).

<h3>What is Time Period of an oscillation?</h3>
  • The time period of an oscillation refers to the time taken by an object to complete one oscillation.
  • It is the inverse of frequency of oscillation; denoted by "T".

Now,

  • \sqrt{\frac{L}{g}}, where L is the length and g is the gravitational constant, is the formula for a pendulum's period.
  • The period will increase as one climbs a very tall mountain because g will slightly decrease.
  • Due to this and the previous issue, the clock runs slowly and it seems that one second is longer than it actually is.

Hence, the grandfather clock will now run slow (Option A).

To learn more about the time period of an oscillation, refer to the link: brainly.com/question/26449711

#SPJ4

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Answer:

the impedance of the circuit is 25.7 ohms.

Explanation:

It is given that,

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Frequency, f = 60 Hz

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Capacitive resistance, X_C=18\ ohms

Inductive resistance, X_L=24\ ohms

We need to find the impedance of the circuit. It is given by :

Z=\sqrt{R^2+(X_L-X_C)^2}

Z=\sqrt{25^2+(24-18)^2}

Z = 25.7 ohms

So, the impedance of the circuit is 25.7 ohms. Hence, this is the required solution.

6 0
3 years ago
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Gemiola [76]

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Explanation:

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¿Qué cantidad de calor absorbió una masa de 4 g de cinc al pasar de 20 °C a<br> 180 °C?
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I hope I helped you^_^

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