H=x and b=x+10
A=hb/2 so
A=x(x+10)/2
A=(x^2+10x)/2 and A=48 so
(x^2+10x)=96
x^2+10x-96-0
x^2-6x+16x-96=0
x(x-6)+16(x-6)=0
(x+16)(x-6)=0, since x>0
x=6in, and since the base is x+10
base=16in
The solution of 2 equations is the point on the grid where they intersect. The 2 equations which intersect at (-1,5) are A and B
Its the first choice.
Answer:
last option
Step-by-step explanation:
(x-h)²+(y-k)²=r²
(x--7)²+(y-4)²=5²
(x+7)²+(y-4)²=25
Answer:
bic4
Step-by-step explanation:
2=b
9=i
3=c
8=h=4 because of censorship
btw ur a bic4 if u came up w/ this lma0