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Rzqust [24]
2 years ago
9

Diane needs a pice of paper whose length is 4 more inchs than width, and the area is as close as possible to 50 in^2. TO the nea

rst whole inch, what should the dimensions of he paper be.
This should be related to multiplying polynomials
*I will mark brainlist plz*
Mathematics
1 answer:
katovenus [111]2 years ago
6 0

Answer:

Width = 5 inches

Length = 9 inches

Step-by-step explanation:

The paper;

Length = (x + 4) inches

Width = x inches

The area is close as possible to 50 square inches.

Since this paper is rectangular in shape; the area of a rectangle is given by:

Area = Length × Width

∴ (x + 4) * x = 50 square inches

x² + 4x = 50

Let the area be equal to 45 square inches;

Applying the quadratic formula, x = 5 or -9

But since we are dealing with length measurements, the value of x = 5 inches.

So the width = 5 inches and;

length = 5 + 4 = 9 inches.

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I get
dybincka [34]

Answer:

Absolute minimum = 1.414

Absolute maximum = 2.828

Step-by-step explanation:

g(x,y)=\sqrt {x^2+y^2} \ constraints: 1\leq x\leq 2 ,\ 1\leq y\leq2

For absolute minimum we take the minimum values of x and y.

x_{minimum} =1\\y_{minimum}=1\\

Plugging in the minimum values in the function.

g(1,1)=\sqrt {1^2+1^2}\\g(1,1) = \sqrt{1+1}\\g(1,1)=\sqrt {2}\\g(1,1)=\pm 1.414\\

Absolute minimum value will be always positive.

∴ Absolute minimum = 1.414

For absolute maximum we take the maximum values of x and y.

x_{maximum} =2\\y_{maximum}=2\\

Plugging in the maximum values in the function.

g(2,2)=\sqrt {2^2+2^2}\\g(2,2) = \sqrt{4+4}\\g(2,2)=\sqrt {8}\\g(2,2)=\pm 2.828\\

Absolute maximum value will be always positive.

∴ Absolute maximum = 2.828

3 0
3 years ago
Need Help ASAP!
poizon [28]
No the solution should only be X=1
5 0
2 years ago
Herman Opened a credit card at a department store with an APR of 24.45% compounded semiannually. What is the APY on his credit c
mash [69]
Semiannually means two. 
so add 24.45 + 24.45
the answer would be A) 48.90%
5 0
3 years ago
PLEASE HELP MEEEEEEEE IM BEGGING
suter [353]
PLEASE HELP MEEEEEEEE IM BEGGING
4 0
2 years ago
Read 2 more answers
5. Write equations in slope-intercept form for three different lines that intersect at (–2, 3). Show your work.
bixtya [17]

Answer:

Equations in slope-intercept form for three different lines that intersect at (–2, 3) are y=-x+1  ,  y=3  and y=x+5

Step-by-step explanation:

General equation of slope intercept form : y-y_1=m(x-x_1)

We are supposed to find equations in slope-intercept form for three different lines that intersect at (–2, 3).

(x_1,y_1)=(-2,3)

Substitute the value in the general equation

y-3=m(x+2)

Now substitute any 3 values of m

At m = -1

\Rightarrow y-3=-x-2 \\\Rightarrow y=-x+1

At m =0

\Rightarrow y-3=0 \\\Rightarrow y=3

At m =1

\Rightarrow y-3=x+2 \\\Rightarrow y=x+5

They all intersect at the given point.

So, equations in slope-intercept form for three different lines that intersect at (–2, 3) are y=-x+1  ,  y=3  and y=x+5

3 0
2 years ago
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