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Rzqust [24]
3 years ago
9

Diane needs a pice of paper whose length is 4 more inchs than width, and the area is as close as possible to 50 in^2. TO the nea

rst whole inch, what should the dimensions of he paper be.
This should be related to multiplying polynomials
*I will mark brainlist plz*
Mathematics
1 answer:
katovenus [111]3 years ago
6 0

Answer:

Width = 5 inches

Length = 9 inches

Step-by-step explanation:

The paper;

Length = (x + 4) inches

Width = x inches

The area is close as possible to 50 square inches.

Since this paper is rectangular in shape; the area of a rectangle is given by:

Area = Length × Width

∴ (x + 4) * x = 50 square inches

x² + 4x = 50

Let the area be equal to 45 square inches;

Applying the quadratic formula, x = 5 or -9

But since we are dealing with length measurements, the value of x = 5 inches.

So the width = 5 inches and;

length = 5 + 4 = 9 inches.

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First, convert the 15% to an actual number that can be used in a calculation. For percents,this is always done by simply dividing the percent (in this case 15%) by 100%.So, the conversational term "15%" becomes 15% / 100% = 0.15 in terms of a real mathematical number.

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i think i got

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