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tino4ka555 [31]
3 years ago
6

Do this please!! :))

Mathematics
2 answers:
GaryK [48]3 years ago
4 0
It would be 23/99 as a fraction
yulyashka [42]3 years ago
3 0
23/99 is your answer
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What is the approximate circumference of a circle with a radius of 8.5 meters? Use π ≈ 3.14.
vovangra [49]
Circumference = 2 pi r
Circumference = 2 x 3.15 x 8.5 m
Circumference = 53.4 metres
4 0
3 years ago
Which is the graph of the solution set of −2x + 5y > 15?
Ilia_Sergeevich [38]

Answer:

given below

Step-by-step explanation:

−2x + 5y > 15

5y > 15 + 2x

if x is 0 then y is 3 and its greater than so increasing

therefore answer is graph A

6 0
2 years ago
use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r
Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt

If we ask that f has continuous (n+1)th derivative we can apply the mean value theorem for integrals. Then, there exists c between a and x such that

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x

Hence,

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .

Thus,

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}

and the Taylor theorem with Lagrange remainder is

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}.

Step-by-step explanation:

5 0
3 years ago
50 cents is _____% of the value of a dollar? Idk pls help me
ICE Princess25 [194]

Answer:

50

Step-by-step explanation:

7 0
3 years ago
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