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dalvyx [7]
3 years ago
7

If all the energy from a 103 W light bulb is emitted at 590.0 nm, what is the energy of each photon in Joule? Planck’s constant

is 6.6 x 10-34 J*s and the speed of light is 3.0 x 108 m/s.
Geography
1 answer:
sergejj [24]3 years ago
8 0

Answer:

Energy of each photon is given by 0.0335\times 10^{-17}j

Explanation:

We have given wavelength of light \lambda =590nm=590\times 10^{-9}m

Speed of light c=3\times 10^8m/sec

Plank's constant h=6.6\times 10^{-34}j-s

We know that energy of photon is given by E=h\nu =\frac{hc}{\lambda }

So energy is given by

E=h\nu =\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{590\times 10^{-9}}=0.0335\times 10^{-17}j

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