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Over [174]
2 years ago
8

the first term of an arithmetic sequence is 5. the eleventh term is 125. what is the common difference of the arithemetic sequen

ce?
Mathematics
2 answers:
Tresset [83]2 years ago
6 0
The first term of an arithmetic sequence is 5. the eleventh term is 125. what is the common difference of the arithemetic sequence?
(1,5);(11,125)

Rate of change=change in y/change in x
=125-5/11-1=120/10=12

☆☆☆☆☆common difference of the arithemetic sequence is 12
ycow [4]2 years ago
5 0

Answer:

d=12

Step-by-step explanation:

The first term of an arithmetic sequence is i.e. a = 5

We are given that eleventh term is 125

Formula of nth term = a_n=a+(n-1)d

Where a is the first term

n is the term no.

d is the common difference

Substitute n = 11

a_{11}=5+(11-1)d

125=5+(11-1)d

120=10d

12=d

Hence The common difference of the arithmetic sequence is 12

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vazorg [7]

Answer:

Step 1: Distribute -2 to 5x and 8

Step 2: Subtract from both sides of the equation 6x

Step 3: Add to both sides of the equation  16

Step 4: Divide both sides of the equation by -16

Step-by-step explanation:

Step 1: Apply the Distributive Property. Then you must  distribute -2 to 5x and 8

Then:

-2(5x+8)=14+6x\\\\-10x-16=14+6x

Step 2: You must apply the Subtraction property of Equality and subtract 6x from both sides of the equation. Then:

-10x-16-6x=14+6x-6x\\\\-16x-16=14

 Step 3: You must apply the Addition property of Equality and add 16 to both sides of the equation. Then:

-16x-16+16=14+16\\\\-16x=30

Step 4: You must apply the Division property of Equality and divide both sides by -16. Then:

\frac{-16x}{-16}=\frac{30}{-16}\\\\x=\frac{30}{-16}\\\\x=-\frac{15}{8}

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