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lianna [129]
2 years ago
14

What is the slope of the line shown below?

Mathematics
1 answer:
aleksklad [387]2 years ago
4 0

Answer:

Step-by-step explanation:

6/5.

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A intersection b formula
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I don't know the formula of the
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3 years ago
An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est
malfutka [58]

Answer:

99% confidence interval for the true mean number of words a third grader can read per minute is [35.5 , 35.9].

Step-by-step explanation:

We are given that a sample of 1584 third graders, the mean words per minute read was 35.7. Assume a population standard deviation of 3.3.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

                           P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean words per minute read = 35.7

            \sigma = population standard deviation = 3.3

            n = sample of third graders = 1584

            \mu = population mean number of words

<em>Here for constructing 99% confidence interval we have used One-sample z test statistics as we know about the population standard deviation.</em>

<em />

So, 99% confidence interval for the population mean, \mu is ;

P(-2.58 < N(0,1) < 2.58) = 0.99  {As the critical value of z at 0.5% level

                                                  of significance are -2.58 & 2.58}  

P(-2.58 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 2.58) = 0.99

P( -2.58 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 2.58 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

P( \bar X-2.58 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.58 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X-2.58 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.58 \times {\frac{\sigma}{\sqrt{n} } } ]

                                                 = [ 35.7-2.58 \times {\frac{3.3}{\sqrt{1584} } } , 35.7+2.58 \times {\frac{3.3}{\sqrt{1584} } } ]

                                                 = [35.5 , 35.9]

Therefore, 99% confidence interval for the true mean number of words a third grader can read per minute is [35.5 , 35.9].

6 0
3 years ago
Write each decimal in expanded form- <br>a.0.493<br>b.1.222
lapo4ka [179]
0.493 = 0.000 + 0.400 + 0.090 + 0.003
It may be also written as: 0.493 = 0 + 0.4 + 0.09 + 0.003

1.222 = 1.000 + 0.200 + 0.020 + 0.002
It may be also written as: 1.222 = 1 + 0.2 + 0.02 + 0.002
8 0
2 years ago
How do I solve for A?
Gwar [14]

*Have to make sure the square root is around the whole problem

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2 years ago
A Floor is 27 Feet By 12 Feet,What is the square Foot Of that floor?
Y_Kistochka [10]

Answer:


Step-by-step explanation:

324 ft squared

6 0
3 years ago
Read 2 more answers
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