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miss Akunina [59]
2 years ago
8

A auto manufacturer claims that one of its car brands has mean MPG (miles per gallon) rating of 40 on the highway. Identify Type

I error for this claim.
a. Fail to reject the claim that mean is 40 MPG when it is actually 40 MPG.
b. Fail to reject the claim that mean is 40 MPG when it is actually not 40 MPG.
c. Reject the claim that mean is 40 MPG when it is actually not 40 MPG.
d. Reject the claim that mean is 40 MPG when it is actually 40 MPG.
Mathematics
2 answers:
Licemer1 [7]2 years ago
8 0

Answer:

d. Reject the claim that mean is 40 MPG when it is actually 40 MPG.

Step-by-step explanation:

The type 1 error could be said to have been made if the null hypothesis is erroneously rejected.

In the scenario above :

The null hypothesis (H0) : mean = 40

Hence, if the Null hypothesis defined above is rejected when in fact the hypothesis that the mean miles per gallon is actually 40.

On the other hand, the type 2 error occurs when a null which is false is not rejected.

Hence, when a true null is rejected, a type 1 error is committed. Similarly, when a false null isn't rejected, then a type 2 error has been committed.

kykrilka [37]2 years ago
6 0

hope this photo helps.enjoy

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3 years ago
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Suppose that 10% of the undergraduates at a certain university are foreign students, and that 25% of the graduate students are f
Deffense [45]

Answer:

0.6154 = 61.54% probability that the student is an undergraduate

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Foreign

Event B: Undergraduate.

There are four times as many undergraduates as graduate students

So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.

Probability the student is foreign:

10% of 80%

25% of 20%. So

P(A) = 0.1*0.8 + 0.25*0.2 = 0.13

Probability that a student is foreign and undergraduate:

10% of 80%. So

P(A \cap B) = 0.1*0.8 = 0.08

What is the probability that the student is an undergraduate?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154

0.6154 = 61.54% probability that the student is an undergraduate

8 0
3 years ago
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Answer:

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256 room between 8 floors so divide the number of rooms by each floor to work out r

256 divided by 8 equals r

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Ahat [919]

Given :-

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To Find :-

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Answer :-

Here in ∆ABC and ∆EDC ,

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Therefore by AA similarity criterion , we can say that ∆ABC ~ ∆EDC . Also we know that corresponding sides of similar triangles are proportional . So ,

→ AC/EC = BC/DC

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→ AC = 8/12 * 9

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