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Nataliya [291]
3 years ago
12

HELP QUICK PLSS

Mathematics
1 answer:
Snezhnost [94]3 years ago
3 0

Answer:

pretty sure the tree's 20 feet

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Determine the value of x for which rls if<br> .<br> m2i = 80 - X; and<br> mz2 = 90 - 2x<br> .
Slav-nsk [51]

Answer:

  x = 10

Step-by-step explanation:

For the lines to be parallel, the two angles must have the same measure:

  80 - x = 90 - 2x

  x = 10 . . . . . . . . . add 2x-80

The value of x must be 10 to make the lines parallel.

6 0
3 years ago
Which expression is equivalent to 15a^8b^4/5a^4b?<br> 3a^2b^4<br> 3a^4b^3<br> 10a^4b^3<br> 10a^4b^4
EleoNora [17]

Answer:

3 a^12 b^5

Step-by-step explanation:

Simplify the following:

(15 a^8 b^4 a^4 b)/5

15/5 = (5×3)/5 = 3:

3 a^8 b^4 a^4 b

3 a^8 b^4 a^4 b = 3 a^(8 + 4) b^(4 + 1):

3 a^(8 + 4) b^(4 + 1)

4 + 1 = 5:

3 a^(8 + 4) b^5

8 + 4 = 12:

Answer: 3 a^12 b^5

5 0
3 years ago
Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm
GuDViN [60]
Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones). 

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

P(x \ \textless \  3) = P(x = 0) + P(x = 1) + P(x = 2)&#10;\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}&#10;\\&#10;\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}&#10;\\&#10;\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}&#10;\\ \indent \boxed{P(x \ \textless \  3) \approx 0.00951836732 }&#10;

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.


5 0
3 years ago
Order these numbers from least to greatest, 749,340;740,999; 740,256
Sindrei [870]
256, 340, 740, 749, 749, 999,
6 0
3 years ago
Answer this for prodigy ASAP
andrezito [222]

Answer:

Hope this Helped ;-;

Step-by-step explanation:

75 is the Answer but the closet is 70

6 0
2 years ago
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