Answer:
The minimum boxes of cookies is 39
Step-by-step explanation:
Let
x ----> the number of boxes of cookies sold
y ----> the number of boxes of candies sold
we know that
The word "at least" means "greater than or equal to"
so
The inequality that represent this problem is

The solution is the shaded area above the solid line 
using a graphing tool
The solution is the shaded area -----> see the attached figure
Find out the minimum boxes of cookies needed to sell to reach the goal
assuming only cookies are sold
For y=0


solve for x

Round up
therefore
The minimum boxes of cookies is 39
The answer is C
4(3-x)+6x=3x+12-x All real numbers are solutions.
10x^2-6x^2 = 4x^2
-64-36 = 100
4x^2 -100 = 0
(2x -10)(2x+10)
X = 2/10 and x = - 2/10
Answer:-1 29/35
Step-by-step explanation: