1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kotykmax [81]
3 years ago
11

A car is sitting still. It accelerates to a constant speed then it decelerates again to zero speed. While the car is acceleratin

g how do the directions of the angular acceleration and angular velocity of one of the wheels compare
Physics
1 answer:
Kobotan [32]3 years ago
5 0

Answer:

in the acceleration process the quantity α and w must increase

the deceleration process the alpha quantity must constant  a direction opposite to the angular velocity

Explanation:

Acceleration and angular velocity are related to linear

           v = w xr

            a = αx r

The bold letters indicate vectors and the cross is a vector product, therefore if

we can see that the relationship between linear and angular variables is direct

therefore in the acceleration process the quantity α and w must increase as well as their linear counterparts

in the deceleration process the alpha quantity must constant as the linear acceleration and must have a direction opposite to the angular velocity

You might be interested in
The main purpose of the turbine in the turbo jet engine is to
Korolek [52]
The main (and only) purpose of the turbine in the turbo jet engine is to drive the air compressor. The turbojet engine works by compressing the air using an inlet and a compressor, then mixing the fuel with the compressed air, then passing the mixture to the combustor, then passing the high pressure air through a turbine and a nozzle.
8 0
3 years ago
The cable holding a 2125 kg elevator has a maximum strength of 21,750 N. What is the maximum upward acceleration the cable can g
vivado [14]

Answer:

10.23m/s^2

Explanation:

GIven data

mass of elevator = 2125 kg

Force= 21,750 N

Required

The maximum acceleration upward

F= ma

a= F/m

a=21,750/2125

a= 10.23m/s^2

Hence the acceleration is 10.23m/s^2

4 0
3 years ago
Someone who is a girl friend me because I’m trying to get simp record
Lelu [443]

Answer:

okay then

Explanation:

6 0
3 years ago
Read 2 more answers
Using a screwdriver to pry off the lid to a paint can is an example of a second class lever.
Serggg [28]
Is this a question? Please provide more information.
8 0
3 years ago
Read 2 more answers
How is the mass and speed of a particle related to its kinetic energy?
jasenka [17]
The higher mass of a particle means it’ll be harder to move, slowing it down and the faster the particle is moving the higher the kinetic energy because there is more movement and pressure within the object with the energy
5 0
3 years ago
Read 2 more answers
Other questions:
  • Which method would likely use less energy? (1) Pushing the heavy box at a slow, constant pace or (2) Pushing the heavy box in fa
    15·1 answer
  • Stars that are composed of matter in which electrons have combined with protons are called ________.
    10·1 answer
  • How is acceleration calculated?
    10·2 answers
  • A wooden log of density 2g/cm3 and volume 50 cm3 fall on the surface of water. Calculate its buoyant force.
    14·1 answer
  • Two equal forces act on two different objects, one of which has a mass ten times as large as the other. The larger object will h
    14·1 answer
  • A small glass bead charged to 8.0nC is in the plane that bisects a thin, uniformly charged, 10-cm-long glass rod and is 4.0 cm f
    10·1 answer
  • A spring of negligible mass and force constant k = 410 N/m is hung vertically, and a 0.200 kg pan is suspended from its lower en
    10·1 answer
  • The number of wavelengths that pass a point each per second is:
    7·1 answer
  • Everyone open this please!
    13·2 answers
  • Which is an example of a wedge?<br> A.<br> B<br> C<br> D
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!