All categories

3 years ago

Why does the number of cooling fins effect the rate of energy transfer from a radiator?

1 answer:

5 0

<span>The number of cooling fins effect increases the rate of energy transfer from a radiator. It is because the cooling fins have an enlarged area allows heat to be transferred into the area away from the object it needs to have less heat with. Thereby cooling the object with cooling fins.</span>

You might be interested in

A 2-kg ball is thrown at 3 m/s. What is the ball's momentum? *

crimeas [40]

Answer:

Given

mass (m) =2kg

velocity (v) =3m/s

momentum (p) =?

Form

p=mv

2kgx3m/s

p=6kg.m/s

the momentum of ball's =6kg.m/s

8 0

3 years ago

I measured my pet dog (Mickey) to be able to run the length of my backyard 500 in 12 seconds. At this rate, how many miles can m

Georgia [21]

The dog runs 300240 miles.

Rate refers to the pace at which something happens. We know that the easiest way to obtain the rate is by the use of proportion. Now we have been told that the dog is able to run 500 miles in 12 seconds.

If the dog runs 500 miles in 12 seconds

The dog runs x miles in 1 second

x = 500 * 1/12

x = 41.7 miles

In two hours we have 2 * 60 * 60 = 7200 seconds

If the dog runs 41.7 miles in 1 second

The dog runs x miles in 7200 seconds

x = 41.7 miles * 7200 seconds/ 1 second

x = 300240 miles

Learn more about proportion:brainly.com/question/2548537

#SPJ1

4 0

2 years ago

Sjskskszpd no djdkzsnkakzx d

Mazyrski [523]

Answer:

jadjsakdjadkjadhfmafkj

Explanation:

4 0

3 years ago

Debris from the solar system strikes the Earth as which of the following

gogolik [260]

Answer: Meteors

Explanation:

7 0

3 years ago

Calculate the speed of a proton after it accelerates from rest through a potential difference of 350 V.

AVprozaik [17]

The speed of a proton after it accelerates from rest through a potential difference of 350 V is $25.86 \times 10^4 ~m/s$ .

Initial velocity of the proton $u = 0$

Given potential difference $\Delta V = 350V$

let's assume that the speed of the proton is $v$ ,

Since the proton is accelerating through a potential difference, proton's potential energy will change with time. The potential energy of a particle of charge $q$ when accelerated with a potential difference $\Delta V$ is,

$U = q \Delta V$

Due to Work-Energy Theorem and Conservation of Energy - <em>If there is no non-conservative force acting on a particle then loss in Potential energy P.E must be equal to gain in Kinetic Energy K.E</em> i.e

$\Delta K = \Delta V$

If the initial and final velocity of the proton is $u$ and $v$ respectively then,

change in Kinetic Energy $\implies \Delta K = \frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}mv^2 - 0$

change in Potential Energy $\implies \Delta U = q\Delta V$

from conservation of energy,

$v= \sqrt{\frac{2q\Delta V}{m}}$

so, $v = \sqrt{\frac{2\times 350 \times 1.6\times 10^{-19}}{1.67 \times 10^{-27}}$

$= 25.86 \times 10^4 ~m/s$

To read more about the conservation of energy, please go to brainly.com/question/14668053

7 0

1 year ago