let the tension force in the rope attached to the sledge be "T"
θ = angle of rope with the horizontal = 40 deg
X = horizontal component of tension force "T" = 100 N
horizontal component of tension force "T" is given as
X = T Cosθ
100 = T Cos40
T = 130.54 N
Y = vertical component of the tension force = ?
vertical component of the tension force is given as
Y = T Sinθ
inserting the values
Y = (130.54) Sin40
Y = 83.91 N
Answer:
crust
Explanation:
it's the outermost layer of the planet.
Answer:
Explanation:
mass of charged particle m = 6 x 10⁻³ kg .
speed of particle v = 4 x 10³ m /s
speed of particle perpendicular to magnetic field = v sin37
= 4 x 10³ sin37
= 2.41 x 10³ m / s
Force on charged particle
= B q v , B is magnetic field , q is charge on particle and v is velocity perpendicular to B
Force = ma
= 6 x 10⁻³ x 8
= 48 x 10⁻³
Force = Bqv
48 x 10⁻³ = 5 x 10⁻³ q x 2.41 x 10³
q = 48 x 10⁻³ / (5 x 2.41)
= 3.98 x 10⁻³C.
( 8.10) x 10^4 J = ½(1010kg)V²
<span>......................= 505V² </span>
<span>( 8.10) x 10^4 J =[(.0505) x 10^4] V² ........<==10^4 cancels </span>
<span>8.10 = .0505 V² </span>
<span>.........______ </span>
<span>V = ²√ 160.4 </span>
<span>V= 12.6 m/s </span>
<span>(that's 12.6m/sec(1km/1000m)(3600secs/1hr) = 45.36kph) </span>
<span> my diagram is wrong, it is just an ordinary car, </span>
Im sure what is broken down is glucose.
(Anyone feel free to correct me if you think I'm wrong)