Answer:

Explanation:
Given

Required
Rewrite using scientific notation
The format of a number in scientific notation is

Where 
So the given parameter can be rewritten as

Express as a power of 10

Hence, the equivalent of the mass of the sun in scientific notation is:

Answer:b
Explanation:the water will not be hot nomore because of the cold water
Trick question? In order to have kinetic energy, an object must be moving. Therefore, in this case, kinetic energy would be 0. If it were asking about potential energy, it would be a different story.
The change in angular displacement as a function of time is the definition given for angular velocity, this is mathematically described as

Here,
= Angular displacement
t = time
The angular velocity is given as

PART A) The angular velocity in SI Units will be,


PART B) From our first equation we can rearrange to find the angular displacement then

Replacing,

