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vova2212 [387]
3 years ago
11

Which has the largest range in air

Physics
2 answers:
laila [671]3 years ago
5 0
I would assume gamma rays because they have the fastest moving partials out of all of them
Gre4nikov [31]3 years ago
4 0
Probably gamma rays. being electromagnetic they'll tend to just keep going and going ...
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A dog in an open field runs 11.0 m east and then 28.0 m in a direction 49.0 ∘ west of north. In what direction must the dog then
Ede4ka [16]

Answer:

\theta=19.03 SE

Explanation:

From the question we are told that:

d_1=11.0m East

d_2=28.0m 49 \textdegree west\ north

d_3=10m south

Generally the equation for Resolutions is mathematically given by

d_x=-11-(-28sin49)

d_x=10.132m

Where

d_y=-11-(28cos49)

d_y=-29.37m

Generally the equation for Direction is mathematically given by

\theta=tan^{-1}(\frac{dx}{dy})

\theta=tan^{-1}(\frac{10.132}{29.37})

\theta=19.03 SE

7 0
3 years ago
An astronomer sees two stars in the sky. Both stars are equally far from Earth, but the first star is brighter than the second s
Dmitrij [34]
It is a younger then the second star.

6 0
3 years ago
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PLEASE HELP WILL GIVE BRANLIEST IF CORRECT
coldgirl [10]

Answer:

Explanation:

  • z: commutator
  • y: brush
  • x: armature

3 0
3 years ago
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A heat recovery system​ (HRS) is used to conserve heat from the surroundings and supply it to the Mars Rover. The HRS fluid loop
Annette [7]

Answer: Volume of Freon = 12.23.10^{3}L

Explanation: First, the temperatures have to be in the same unit, so all the tmeperatures is transformed into Kelvin:

T₁ = 192K

T₂ = \frac{5}{9}. (F - 32)+273.15

T₂ = \frac{5}{9}. (- 65 - 32)+273.15

T₂ = 219.26K.

Second, BTU is an unit of energy. It can be transformed into Joules by the relation 1BTU = 1055.06J.

Q = 1055.06 . 46.9 = 49482.314J

The letter Q represents Heat and is calculated as Q = m.Cp.ΔT, where:

m is mass of the element;

Cp is the heat capacity specific for each element;

ΔT is the difference between the final and initial temperature;

Third, it will be needed the properties of the Freon:

Freon (CF2Cl2) = 120.91g/mol; Cp = 74J/mol.K; ρ = 1.49kg/m³

Fourth, we calculate the mass of Freon necessary for the remove of 46.9BTU of energy from the system:

Q = m.Cp.ΔT

m=\frac{Q}{c(T-T_{0} )}

m = \frac{49482.314}{74(219.26-192)}

m = 18228.214g or m=18.228Kg

Fifth, using the density of Freon, Volume can be found

ρ = \frac{m}{V}

V = m / ρ

V = 18.228 / 1.49

V = 12.23m³

As SI for density is Kg/m³, the volume found is in m³.

Cubic meters is related to Liters as the following: 1m³=1000l.

So, volume of Freon = 12.23.10^{3}L

The volume of Freon needed is 12.23.10^{3}L.

7 0
3 years ago
Select the correct answer.
sashaice [31]

Answer:

Waxing Gibbous

Explanation:

4 0
4 years ago
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