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Strike441 [17]
3 years ago
15

Jack and Walter work in a store's gift-wrapping department. Jack can wrap 28 boxes in 2 hours, while Walter takes 3 hours to wra

p 36 boxes of the same size. One day they work together for t hours to gift wrap 65 boxes. Which equation models this situation?
Mathematics
2 answers:
Delvig [45]3 years ago
7 0
<span>Together they wrap 14+12 = 26 boxes per hour. 
t hours × 26 boxes/hour = 65 boxes 

C</span><span>
</span>
MArishka [77]3 years ago
5 0

Answer:

t hours × 26 boxes/hour = 65 boxes

Step-by-step explanation:

Jack can wrap 28 boxes in 2 hours.

i.e. In 1 hour Jack can wrap 14 boxes.

while Walter takes 3 hours to wrap 36 boxes of the same size.

i.e. in 1 hour Walter can wrap 12 boxes.

Together they wrap 14+12 = 26 boxes per hour.  

In t hour they will wrap 26t boxes

Hence, equation that represents this situation is:

 t hours × 26 boxes/hour = 65 boxes

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X/3-15=-2 solve for x
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Answer:

x = 45

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

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Equation at the end of step  1  :

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Step  2  :

<u>Rewriting the whole as an Equivalent Fraction :</u>

Subtracting a whole from a fraction

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<u>Equivalent fraction :</u> The fraction thus generated looks different but has the same value as the whole

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Adding fractions that have a common denominator :

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

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Equation at the end of step  2  :

\frac{x-45}{3} =0

Step  3  :

When a fraction equals zero :

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

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Now, on the left hand side, the  3  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  x-45  = 0

Solving a Single Variable Equation :

<u>Solve  :</u>    x-45 = 0

Add  45  to both sides of the equation :

x = 45

One solution was found :

x = 45

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