2 years ago

Sam

Mathematics

1 answer:

Nina [5.8K]2 years ago

6 0

If it’s 6 full weeks it’s 93 hours

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Evaluate 2313+1302 in base

Lelechka [254]

2313 in base10 - 183

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2 years ago

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Please help. <br> Find the value of h in the triangle.

dybincka [34]

1/2×12m×18.2m=109.2m2
109.2m2÷21.8m÷1/2=10m(nearest whole number)
h=10m

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2 years ago

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(Find the HCF of):<br>p^2+4pq+4q^2, p^4 + 8pq^3 and 3p^4 - 10p^2q^2+ p^3q

kow [346]

Answer:

12pq

Step-by-step explanation:

i dont know tbh but i try my best to help out now anyways

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2 years ago

Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9

natulia [17]

Parameterize $C$ by

$\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle$

where $0\le t\le\pi$ . Then the line integral is

$\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt$
$=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt$
$=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt$

Take $u=\cos t$ , then

$=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du$
$=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du$
$=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du$
$=54$

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3 years ago

What is the equation of the line in point-slope form that has a slope of -3 and passes through the point (5, 9)?

krek1111 [17]

Answer:

$y-9=-3(x-5)$

Step-by-step explanation:

The equation of the line in point-slope form is given as

$y-y_1=m(x-x_1)$

Here m=-3 and (x1, y1)=(5, 9)

Therefore,

$y-9=-3(x-5)$

8 0

2 years ago