<h3>Solution:</h3>
![2 \frac{1}{4} \times 3 \frac{1}{5} \\ = \frac{9}{4} \times \frac{16}{5} \\ = \frac{9 \times 4}{5} \\ = \frac{36}{5} \\ = 7 \frac{1}{5}](https://tex.z-dn.net/?f=2%20%5Cfrac%7B1%7D%7B4%7D%20%20%5Ctimes%203%20%5Cfrac%7B1%7D%7B5%7D%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B9%7D%7B4%7D%20%5Ctimes%20%20%5Cfrac%7B16%7D%7B5%7D%20%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B9%20%5Ctimes%204%7D%7B5%7D%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B36%7D%7B5%7D%20%20%5C%5C%20%20%3D%207%20%5Cfrac%7B1%7D%7B5%7D%20)
<h3>Answer:</h3>
![7 \frac{1}{5}](https://tex.z-dn.net/?f=7%20%5Cfrac%7B1%7D%7B5%7D%20)
<h3>Hope it helps..</h3><h3>ray4918 here to help..</h3>
Answer:
There are approximately 2907 ounces in 82.4 kilograms
Step-by-step explanation:
I multiplied the mass value by 35.274 then rounded up.
Answer:
90
Step-by-step explanation:
The sum of squares of the deviation from mean=sum(x-xbar)²=?
x
12
6
15
9
18
12
xbar=sumx/n
xbar=(12+6+15+9+18+12)/6=72/6=12
x x-xbar (x-xbar)²
12 12-12=0 0
6 6-12=-6 36
15 15-12=3 9
9 9-12=-3 9
18 18-12=6 36
12 12-12=0 0
sum(x-xbar)²=0+36+9+9+36+0=90
So, the sum of squares of the deviations from the mean is 90.
Divide 55 by 5/7, and you’ll get x.
55/(5/7) = 55*(7/5) = 11*7 = 77 = x
18, 38, 43, 47, 55, 88, 90.
hope this helps!