Equivalent to 180 degrees.
90 degrees clockwise +90 degrees
If solving for p, it is 239.98 bc when 284.97+194.99, 2p=479.96
Answers:
- a) 15000 represents the starting amount
- b) The decay rate is 16%, which means the car loses 16% of its value each year.
- c) x is the number of years
- d) f(x) is the value of the car after x years have gone by
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Explanation:
We have the function f(x) = 15000(0.84)^x. If we plug in x = 0, then we get,
f(x) = 15000(0.84)^x
f(0) = 15000(0.84)^0
f(0) = 15000(1)
f(0) = 15000
In the third step, I used the idea that any nonzero value to the power of 0 is always 1. The rule is x^0 = 1 for any nonzero x.
So that's how we get the initial value of the car. The car started off at $15,000.
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The growth or decay rate depends entirely on the base of the exponential, which is 0.84; compare it to 1+r and we see that 1+r = 0.84 solves to r = -0.16 which converts to -16%. The negative indicates the value is going down each year. So we have 16% decay or the value is going down 16% per year.
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The value of x is the number of years. In the first section, x = 0 represented year 0 or the starting year. If x = 1, then one full year has passed by. For x = 2, we have two full years pass by, and so on.
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The value of f(x) is the value of the car after x years have gone by. We found that f(x) = 15000 when x = 0. In other words, at the start the car is worth $15,000. Plugging in other x values leads to other f(x) values. For example, if x = 2, then you should find that f(x) = 10584. This means the car is worth $10,584 after two years.
we need to find 1% of 10000 first
so we divide 10000:100= 100 (that's 1%)
to find the 60% which will be accepted we multiply 100 × 60 = 6000 students accepted
of those 6000 we need to find 50% which is ½ so we basically just divide by 2, aka 6000 : 2 = 3000 people which will be enrolled
