Answer:
C. Bulldogs
Step-by-step explanation:
In this question, we want to compare several numbers with different denominators and find out which number is the least. To compare this number, we have to change the denominator into the same number by finding the least common multiple (LCM) of the 4 numbers. The factor of each number will be:
3= 3 ^1
5= 5^1
8= 2 * 2 * 2 = 2^3
2= 2^1
We can find the LCM by multiplying a higher exponent of each prime number. The LCM will be:3^1 * 5^1 * 2^3 = 120
Each number will be:
Tiger= 2/3 * 40/40= 80/120
Redbird = 4/5 * 24/24= 96/120
Bulldogs = 3/8 * 15/15 = 45/120
Titans = 1/2 * 60/60 = 60/120
As you can see, the team with the lowest chance to play is Bulldogs = 45/120
If
is the first number in the progression, and
is the common ratio between consecutive terms, then the first four terms in the progression are
![\{x,xr,xr^2,xr^3\}](https://tex.z-dn.net/?f=%5C%7Bx%2Cxr%2Cxr%5E2%2Cxr%5E3%5C%7D)
We want to have
![\begin{cases}xr^2-x=12\\xr^3-xr=36\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7Dxr%5E2-x%3D12%5C%5Cxr%5E3-xr%3D36%5Cend%7Bcases%7D)
In the second equation, we have
![xr^3-xr=xr(r^2-1)=36](https://tex.z-dn.net/?f=xr%5E3-xr%3Dxr%28r%5E2-1%29%3D36)
and in the first, we have
![xr^2-x=x(r^2-1)=12](https://tex.z-dn.net/?f=xr%5E2-x%3Dx%28r%5E2-1%29%3D12)
Substituting this into the second equation, we find
![xr(r^2-1)=12r=36\implies r=3](https://tex.z-dn.net/?f=xr%28r%5E2-1%29%3D12r%3D36%5Cimplies%20r%3D3)
So now we have
![\begin{cases}9x-x=12\\27x-3x=36\end{cases}\implies x=\dfrac32](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D9x-x%3D12%5C%5C27x-3x%3D36%5Cend%7Bcases%7D%5Cimplies%20x%3D%5Cdfrac32)
Then the four numbers are
![\left\{\dfrac32,\dfrac92,\dfrac{27}2,\dfrac{81}2\right\}](https://tex.z-dn.net/?f=%5Cleft%5C%7B%5Cdfrac32%2C%5Cdfrac92%2C%5Cdfrac%7B27%7D2%2C%5Cdfrac%7B81%7D2%5Cright%5C%7D)
Im not understanding what you are asking
I do believe that the answer is 9/10
Step-by-step explanation:
y=-27
...................