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hichkok12 [17]
3 years ago
10

Taylor has some pack of stickers.There are six stickers in each pack.He give each of his friends a sticker and has fourteen stic

kers leftover.Write the number of packs he has left as a mixed number.
Mathematics
1 answer:
kykrilka [37]3 years ago
6 0
He has 2.3 packs left. So he has 2 packs and 2 stickers so it would be 2 2/6
You might be interested in
I need to find the median ,mean,mode,range,and
Makovka662 [10]
Median: 23.5
12 and 35 are in the middle so you add them and divide by 2, leaving you 
23.5 as your median.
Mean: 41.3
Add all numbers together and divide the sum by the number of numbers added. So all numbers added together equals 413. Divide by ten the nuber of numbers added. 413/10 equals 41.3. 
Mode: 99
The number that appears most often. In this case, 99 would be the mode. 
Range: 98
The lowest number subtracted from the highest number. 99-1 equals 98.
IQR: 84.75

Hope this helped! :)

8 0
3 years ago
Read 2 more answers
The sample space listing the eight simple events that are possible when a couple has three children is {bbb, bbg, bgb, bgg, gbb,
NNADVOKAT [17]

Answer:

bbbb,

bbbg, bbgb, bgbb, gbbb,

bbgg, bgbg, bggb, gbgb, gbbg, ggbb,

bggg, gbgg, ggbg, gggb,

gggg

Step-by-step explanation:

3 children: bbb, bbg, bgb, gbb, bgg, gbg, ggb, ggg

4 children: bbbb, bbbg, bbgb, bgbb, gbbb, bbgg, bgbg, bggb, gbgb, ggbb, bggg, gbgg, ggbg, gggb, gggg

You need to take a methodological approach;

The 2 easiest are the possibility of all boys and all girls;

Then consider 3 boys and 1 girl:

bbbg, bbgb, bgbb, gbbb

Then 2 boys and 2 girls:

bbgg, bgbg, bggb, gbgb, gbbg, ggbb

Lastly, 1 boy and 3 girls:

bggg, gbgg, ggbg, gggb

In total, there are 16 possibilities

P.S. interesting to note is that the number of possibilities here follows the pattern of Pascal's triangle:

       1

     1   1

   1  2  1

 1  3  3  1

1  4  6  4  1

The last row is relevant here;

There is 1 possibility where there are 4 boys;

There are 4 possibilities (in terms of the order of birth) where there are 3 boys and 1 girl;

There are 6 possibilities where there are 2 boys and 2 girls

There are 4 possibilities where there is 1 boy and 3 girls;

There is 1 possibility where there are 4 girls;

The pattern ∴ is 1 4 6 4 1, as the 5th row of Pascal's triangle reads;

If your talking about 3 children, it would match the 4th row of Pascal's triangle;

So, 1 possibility of 3 boys;

3 possibilities of 2 boys and 1 girl;

3 possibilities of 1 boy and 2 girls;

And 1 possibility of 3 girls;

If your talking about 10 children, it would match the 11th row of Pascal's triangle.

(Maths can be so cool XD)

7 0
3 years ago
Jack and Julio each improved their yards by planting daylilies and geraniums. They bought their supplies from the same store.
o-na [289]

Cost of one daylily is $2 and cost of one geranium is $4.

Step-by-step explanation:

Let,

Cost of one daylily = x

Cost of one geranium = y

According to given statement;

x+5y=22    Eqn 1

13x+y=30    Eqn 2

From Eqn 1;

x=22 - 5y

Putting this value of x in Eqn 2;

13(22-5y)+y=30\\286-65y+y=30\\-64y=30-286\\-64y=-256

Dividing both sides by -64

\frac{-64y}{-64}=\frac{-256}{-64}\\y=4

Putting y=4 in Eqn 1

x+5(4)=22\\x+20=22\\x=22-20\\x=2

Cost of one daylily is $2 and cost of one geranium is $4.

Keywords: linear equation, substitution method

Learn more about substitution method at:

  • brainly.com/question/605571
  • brainly.com/question/5873564

#LearnwithBrainly

4 0
3 years ago
Which one should I choose
Allushta [10]

Answer:

100% B

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help me!!!! And please provide steps w/ answer!!
Anvisha [2.4K]
1. Box off the squares (which you did)
2. Solve the area of the squares: (10cm x 10cm = 100cm each square)
3. Solve the area of the rectangle that is left: (you would do 40cm x 10cm since the other 10cm went with the square. The rectangle should end up to be 400cm.
4. Add the areas: 100cm + 100cm +400cm = 600cm
600cm is the answer
7 0
3 years ago
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