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zavuch27 [327]
3 years ago
15

How many solutions exist for the given equation? 3(x -2) = 22-x

Mathematics
1 answer:
OLEGan [10]3 years ago
6 0

Answer: 1

Step-by-step explanation:

3(x-2) = 22-x

3x - 6 = 22 - x

4x = 28

x = 7

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Given k(x) =x^3-2x, find k (3)
nadezda [96]

Answer:  21

Step-by-step explanation:

k(x) =x^3-2x

k(3) =3^3-2*(3)

k(3) =27-6

k(3) = 21

5 0
3 years ago
find the third,fifth and seventeenth terms of the sequence described by each explicit formula f(n)=8+3(n-1) and how you got it
alexira [117]

Answer:

Step-by-step explanation:

plug in 3 , 5 and 17 for n

8 + 3(3 -1) = 8 + 6 = 14

8 + 3(5-1) = 8 + 12 = 20

8 + 3(17-1) = 8 + 48 = 56

3 0
3 years ago
Is 2750 a reasonable answer for 917 times 33
hodyreva [135]
No because 917 times 33 is 30261
6 0
3 years ago
Carolyn has been contributing to a pre-tax retirement account. Her youngest child is ready to start college, and Carolyn wants t
Flauer [41]

Answer: 77,089.64 or 83,256.81

Step-by-step explanation:

Either or because it doesnt specify is she has to pay 10% and 25% or 10% early and 15% later on. If you know then the lower answer is 10% now and 15% later on. GL!

6 0
2 years ago
Matthew launches a ball at 34 meters/sec from a 28 meter tall platform. The function of the ball's height (h) at time (t) second
Alex17521 [72]

Answer:

17 seconds

Step-by-step explanation:

h(t) represents height, we want to know when the ball will return to a height of 28 feet.  So our equation is..

28 = -2t² + 34t + 28

Now solve for t...

0 = -2t² + 34t         (subtract 28 from both sides)

0 = t² - 17t             (divide both sides by -2)

0 = t(t - 17)          (factor out a t)

So

t = 0

or

t - 17 = 0

  t = 17          

0 seconds is the initial height.  At 17 seconds, the ball will return to that height

5 0
3 years ago
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