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saul85 [17]
3 years ago
5

A square has a perimeter of 8 and one vertex at (2, 2). What could be the location of another vertex of this shape? A) (1, 5) B)

(-2, 2) C) (2, 3) D) (0, 0)
Mathematics
2 answers:
leonid [27]3 years ago
6 0
D 0, 0 hopefully you got it right good luck
Lunna [17]3 years ago
5 0

Answer:

D) (0,0)

Step-by-step explanation:

It is a square so each side is 2 units because

8/4 = 2

If the first point is at (2,2) we need to find which other point is 2 away from the first one. Or two away from where that point would be since there are 3 other corners.

We can rule out A and C because they are an odd number away. B is too far away because he's distance is 4.

So the other point is (0,0)

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What is negative 5 5/6–2 3/5
dangina [55]

Answer:

the answer is -8 13/30

Step-by-step explanation:

4 0
3 years ago
675/8 as a mixed number in simplest form.
Alex777 [14]

The answer is 84 3/8 because 672 and the left over 3 so it would be 84 3/8.

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8 0
3 years ago
Find the x- and y-intercepts for the linear equation.<br> – 3x + 5y = 15
Paladinen [302]

Answer:

x-intercept: (-5,0)

y-intercept: (0,3)

Step-by-step explanation:

y-intercept: when x = 0

-3(0) + 5y = 15

5y = 15

y = 3

x-intercept: when y = 0

-3x + 5(0) = 15

-3x = 15

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6 0
3 years ago
Read 2 more answers
Which expressions are equivalent to<br>-6 +49 + (-69) ?​
kiruha [24]

Answer:

-26

Step-by-step explanation:

-6+49+(-69)

43+(-69)

43-69

-26

3 0
3 years ago
Teresa graphs the following 33 equations: y=2xy=2x, y=x2+2y=x2+2, and y=2x2y=2x2. She says that the graph of y=2xy=2x will event
Neko [114]
The correct question is 
<span>Teresa graphs the following 3 equations: y=2x, y=x2+2, and y=2x2. She says that the graph of y=2x will eventually surpass both of the other graphs. Is Teresa correct? Why or why not?

we have that
y=2x
y=x</span>²+2
y=2x²

using a graph tool
see the attached figure

<span>We can affirm the following
</span>the three graphs present the same domain-----> the interval (-∞,∞)

The range of the graph y=2x  is the interval (-∞,∞)

The range of the graphs y=x²+2 and y=2x² is the interval [0,∞)

therefore
<span>Teresa is not correct because the graph of y = 2x will not surpass the other two graphs since in the interval of [0, infinite) the three graphs present the same range</span>

3 0
3 years ago
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