A square has a perimeter of 8 and one vertex at (2, 2). What could be the location of another vertex of this shape? A) (1, 5) B) (-2, 2) C) (2, 3) D) (0, 0)
2 answers:
D 0, 0 hopefully you got it right good luck
Answer:
D) (0,0)
Step-by-step explanation:
It is a square so each side is 2 units because
8/4 = 2
If the first point is at (2,2) we need to find which other point is 2 away from the first one. Or two away from where that point would be since there are 3 other corners.
We can rule out A and C because they are an odd number away. B is too far away because he's distance is 4.
So the other point is (0,0)
You might be interested in
Answer:
The triangles are congruent by
SSS
Step-by-step explanation:
Given:
First Label the Diagram:
AB ≅ CD
AD ≅ BC
To Prove:
Δ ABC ≅ Δ CDA
Proof:
In Δ ABC and Δ CDA
AB ≅ CD ....……….{Given}
BC ≅ DA …………..{Given}
AC ≅ AC ……….{Reflexive Property}
Δ ABC ≅ Δ CDA ….{ By Side-Side-Side test}
18.0 1
Answer:
c
Step-by-step explanation:
I think so I might not be right but I'm sure it's c
<span>4*(5+3)-(8/4)+3*4
