Answer:
485.76 g of CO₂ can be made by this combustion
Explanation:
Combustion reaction:
2 C₄H₁₀(g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (g)
If we only have the amount of butane, we assume the oxygen is the excess reagent.
Ratio is 2:8. Let's make a rule of three:
2 moles of butane can produce 8 moles of dioxide
Therefore, 2.76 moles of butane must produce (2.76 . 8)/ 2 = 11.04 moles of CO₂
We convert the moles to mass → 11.04 mol . 44g / 1 mol = 485.76 g
Answer:
Their electrons are placed in a higher number of orbitals
Explanation:
- Suppose a element be Ga .
The atomic no is 31
The configuration is given by
Or
![\\ \sf\longmapsto [Ar]3d^{10}4s^24p^1](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5BAr%5D3d%5E%7B10%7D4s%5E24p%5E1)
