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MrMuchimi
3 years ago
6

Calculate the volume occupied by 55.5 moles of water at STP.

Chemistry
1 answer:
Tems11 [23]3 years ago
4 0

Answer:

Volume occupied by 55.5 moles of water gas at STP = 1240 Liters.

Explanation:

1st keep in mind that 'volume' in the context of problems like this apply only to the gas phase form of the substance. Water in solid form (ice) or liquid form (liquid water) do not apply. Volume in this case is referred to as 'molar volume' and is a gas occupying 22.4 liters at STP conditions (0°C, 1Atm).

So, if 1 molar volume of water gas (steam) occupies 22.4 Liters at STP, then 55.5 moles of water gas occupies 22.4 Liters/mole x 55.5 moles = 1243.2 Liters, or 1240 Liters (3 sig. figs.).   :-)

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In fractional distillation, liquid - liquid mixtures are separated based on the differences in boiling point of their components. Let us examine the boiling points of the component of the mixtures:  

     Ethanol                  78⁰C

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We see that the liquids in the mixture have different boiling points. In this process, the mixture is heated in a distillation column. When the boiling point of any component is reached, it will rise up in the column and can be channeled to a condenser where it is cooled and collected.

The liquid with the least boiling point is first separated with the one with the highest boiling is recovered last:

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Learn more:

Physical properties brainly.com/question/10972073

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11.19 %

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If H = 1.008 u and O = 16.00 u, then

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