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LenaWriter [7]
3 years ago
11

Indicate which of the following criteria are important for the selection of a buffer to use in an in vitro biochemical reaction.

(Select all that apply.)
a. The molecular weight of the chosen buffer should be in the range of 150 g/mol to 650 g/mol.
b. The chosen buffer should not interfere with the biochemical reaction.
c. The makeup of the chosen buffer should include only carbon, hydrogen, nitrogen, oxygen, and phosphorus.
d. The pKa of the chosen buffer should be close to the optimal pH for the biochemical reaction.
e. The chosen buffer should have a much higher concentration of its protonated species compared to the concentration of its deprotonated species at the optimal pH for the biochemical reaction.
Chemistry
1 answer:
JulsSmile [24]3 years ago
7 0

Answer:

The correct answer is: d. The pKa of the chosen buffer should be close to the optimal pH for the biochemical reaction.

Explanation:

The buffer resist or maintain the change in pH in case of Acid or basic addition to the solution. The buffer capacity should be within one or two pH units when compared to the optimal pH.

Thus it is important to select a buffer with pKa close to the optimum pH of the reaction because the ability for the buffer to maintain the pH is is great at the pH close to pKa.

You might be interested in
#1.Which of the following best identifies base 1? A) purine. B) pyrimidine. C) cytosine. D) nucleotide. #2. Which of the followi
alex41 [277]
Here are the list of nucleo bases : adenine , Thymine, Guanine , Cytosine

Adenine pairs with Thymine, and Guanine pairs with Cytosine

Adenine + Guanine = Purine
Thymine + Cytosine = Pyrimidine

So the answer for number 1 will be : Purine, since Adenine is not the choice

And the answer for number 2 is Guanine

hope this helps

 


6 0
3 years ago
1. What is the relationship between the concentration of the hydronium and hydroxide
Hitman42 [59]

Answer:

- Neutral solutions: concentration of hydronium equals the concentration of hydroxide.

- Acid solutions: concentration of hydronium is greater than the concentration of hydroxide.

- Basic solutions concentration of hydronium is lower than the concentration of hydroxide.

Explanation:

Hello,

It is widely known that the pH of water is 7, therefore the pOH of water is also 7 based on:

pH+pOH=14

In such a way, we can compute the concentration of hydronium and hydroxide ions as shown below:

pH=-log([H^+])\\

[H^+]=10^{-pH}=10^{-7}=1x10^{-7}M

pOH=-log([OH^-])

[OH^-]=10^{-pOH}=10^{-7}=1x10^{-7}M

Thus, we notice that the relationship between the concentration of the hydronium is equal for water or neutral solutions. Moreover, if we talk about acid solutions, pH<OH therefore the concentration of hydronium is greater than the concentration of hydroxide. On the other hand if we talk about basic solutions, pH>OH therefore the concentration of hydronium is lower than the concentration of hydroxide.

Best regards.

4 0
3 years ago
Identify which subatomic particles match each of these descriptions. Specifically, determine whether the following descriptions
iren2701 [21]

Answer:

1. Protons

2. Electrons

3. Neutrons

4. Protons and neutrons

5. Electrons

Explanation:

The protons are the only positive sub-atomic particles and the have a charge of +1.

The Electrons are the only negative subatomic particles and they have a charge of -1

Neutrons do not have any charge but they have the same mass as the protons

The nucleus of an atom is where most of the atomic masses are concentrated and it houses the neutrons and protons

The electrons reside outside the nucleus and they have a much more lesser mass compared to the neutrons and protons

5 0
3 years ago
A voltaic cell is constructed in which the anode is a Zn|Zn2+ half cell and the cathode is a Fe2+|Fe3+ half cell. The half-cell
zmey [24]

Answer:

See below explanation

Explanation:

Checking the reduction potencials:

Zn⁺²/Zn° , E° = -0.76 V

Fe⁺²/Fe° , E° = -0.44 V

For which Fe⁺² will be the ion that will reduce, and Zn° will lose electrons

ANODE:    Zn° ⇄ Zn⁺² + 2e⁻

CATODE: Fe⁺² + 2e⁻ ⇄ Fe°

NET CELL REACTION: FeSO₄ (ac) + Zn° ⇄ Fe° + ZnSO₄ (ac)

In the external circuit, electrons will migrate from anode (Zn|Zn⁺²) to catode (Fe|Fe⁺²), and in the salt bridge; anions migrate from Fe⁺²|Fe compartment to Zn|Zn⁺² compartment

7 0
3 years ago
Aight imma let you guys i
katrin [286]

Answer:

b

Explanation:

it is right

6 0
3 years ago
Read 2 more answers
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