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3 years ago

12

Can someone please help me

1 answer:

umka2103 [35]3 years ago

6 0

Answer:

28/43

Step-by-step explanation:

The question asks what is the probability that Marley picks out a blue or yellow marble.

In total, there are 43 marbles.

In total, there are 28 blue and yellow marbles. (18+10=28)

So, the answer would be 28/43

Hope this helps

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Solve the following equation and show all of your steps: x^2+x−1=0

DaniilM [7]

Quadratic formula since this trinomial is not factorable.
$\frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ \frac{ - 1 + - \sqrt{ {(1)}^{2} - 4(1)( - 1) } }{2(1)} \\ \frac{ - 1 + - \sqrt{1 + 5} }{2} \\ \frac{ - 1 + - \sqrt{6} }{2} \\ x = \frac{ - 1 + \sqrt{6} }{2} \\ x = \frac{ - 1 - \sqrt{6} }{2}$

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3 years ago

Which graph represents the function f(x)= 0.2^x + 3

Dennis_Churaev [7]

The third graph or bottom left graph represents $f(x) = 0.2^{x} + 3.$

Step-by-step explanation:

Step 1:

To determine which of the given graphs represents the equation $f(x) = 0.2^{x} + 3$ , we substitute some values in the place of x.

When $x=0,$ $f(x) = 0.2^{x} + 3, f(0) = 0.2^{0} + 3= 4.$

Anything with an exponent of 0 will equal 1.

So the graphs on the right side cannot be the answers.

Step 2:

Now we substitute another value to determine which graph represents $f(x) = 0.2^{x} + 3.$

When $x=1,$ $f(x) = 0.2^{x} + 3, f(1) = 0.2^{1} + 3= 4.2.$

The value of f(x) when $x=1$ is lesser than the value of f(x) when $x =0.$

So the third graph or bottom left graph represents $f(x) = 0.2^{x} + 3.$

5 0

3 years ago

tia_tia [17]

Answer:

aakkakjasjsbsvshsjsbsbanjasjsjj

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2 years ago

Express each product in the simplest form.

ololo11 [35]

4 is probably the answer. Hope this helps. :)

5 0

3 years ago

Read 2 more answers

4, 12, 20, ..<br> Find the 46th term.

lutik1710 [3]

Answer:

46th term of the sequence is 364

Step-by-step explanation:

first term = 4

common difference = 12 - 4 = 8

46th term = first term+(46 - 1)×common difference

so,

46th term = 4 + ( 45 ) × 8
46th term = 4 + 360
46th term = 364

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em>

3 0

2 years ago