Question

What three consecutive numbers have a sum of 126

Answer 1

Answer:

41, 42, 43

Step-by-step explanation:

three consecutive numbers

$x + (x+1) + (x+2)$

have a sum of 126

$x + (x+1) + (x+2) = 126\\x + x + 1 + x + 2 = 126\\3x + 3 = 126\\3x = 123\\x = 41$

41 is our smallest number, so 42 and 43 are the two other numbers

Note: With these sum of N consecutive numbers problems, you can find the middle number by doing (Sum/N)

Answer 2

Answer:41

Step-by-step explanation:

x+(x+1)+(x+2)=126

3x+3 =126

3x =126-3

3x =123

x =123/3

x=41