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lys-0071 [83]
3 years ago
14

What is the slope of a line that passes through the origin and the point (6, 14)?

Mathematics
2 answers:
Mrrafil [7]3 years ago
7 0

Answer:

14/6 or 2 1/3

Step-by-step explanation:

m=y2-y1/x2-x1

14-0=14

6-0=6

14/6 or 2 1/3

hope this helps :3

if it did pls mark brainliest

sorry if it is wrong

ivann1987 [24]3 years ago
3 0
It would be 14/6 so the slope would be 2.33 because it’s always y/x.
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A circle with a diameter of 2 inches and a square with 2-inch sides have the same center. Find the area of the region that is in
n200080 [17]
Area of square = 4 square inches
Area of circle = PI * radius ^2
Area of circle = 3.14 * 1^2
Area of circle = 3.14 square inches
Area inside the square and outside the circle =
4 -3.14 = .86 square inches.
answer is .9 square inches


5 0
3 years ago
HELP ASAP!! WILL GIVE BRAINLIEST ❤️
mr Goodwill [35]

Answer:

m=-3

The slope is negative.

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, 19)

Point (-1, 7)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{7-19}{-1-(-5)}
  2. Simplify:                        m=\frac{7-19}{-1+5}
  3. Subtract/Add:               m=\frac{-12}{4}
  4. Divide:                          m=-3
8 0
3 years ago
Mei has 8 jars of soup. Each jar contains 300 milliliters of soup. What is the smallest pot Mei can use to heat all the soup?
balu736 [363]
<h3>Mei can use the smallest pot with capacity of 2400 milliliters to heat all the soup</h3><h3><u> Solution:</u></h3>

Given that,

Mei has 8 jars of soup

Each jar contains 300 milliliters of soup

Therefore,

Total amount of soup = 300 ml x 8 jars

Total amount of soup = 300 \times 8

Total amount of soup = 2400 ml

Hence, Mei can use the smallest pot with capacity of 2400 milliliters to heat all the soup          

8 0
4 years ago
What is the square root of 28
Oduvanchick [21]

The decimal form would be 5.29150262

6 0
3 years ago
Read 2 more answers
Simplify <br> (5x^2y^3)^2x(2x^3y^4)^3
Misha Larkins [42]
Remember
(abc)^x=(a^x)(b^x)(c^x)
and
(x^m)(x^n)=x^{m+n}
and
(x^m)^n=x^{mn}
so
I'm going to assume that that x after the 2 exponent is multiply and not a variable to be multiplied, if it is go to option 2
(5x^2y^3)^2(2x^3y^4)^3=
(5^2)((x^2)^2)((y^3)^2)(2^3)((x^3)^3)((y^4)^3)=
(25)(x^4)(y^6)(8)(x^9)(y^{12})
200x^{13}y^{18}

2. if that x was a variable and nod a multiply then
200x^{14}y^{18}


7 0
3 years ago
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