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olga2289 [7]
3 years ago
5

Can anyone help with this problem ASAP it’s a timed test PLzzzz

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
5 0

Answer:

It's (D)...............................

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Help me anwser!I really need help
Viefleur [7K]
Use a calculator to answer
5 0
3 years ago
Consider the quadratic function f(x) = –2x2 5x – 4. the leading coefficient of the function is?
evablogger [386]

Answer:

\text{-2 is the leading coefficient of the quadratic equation }f(x)=-2x^2+5x-4

Step-by-step explanation:

Given the quadratic function

f(x)=-2x^2+5x-4

we have to find the leading coefficient of given quadratic equation.

\text{The general form of quadratic equation is }ax^2+bx+c=0

The coefficient of x^2 i.e a is known as the leading coefficient.

Comparing given equation with the standard equation, we get

a=-2

\text{Hence, -2 is the leading coefficient of the quadratic equation }f(x)=-2x^2+5x-4

3 0
3 years ago
Read 2 more answers
Rewrite the division problem as multiplication:
Pani-rosa [81]

Answer:

What is the problem??? If you didn't need an actual problem solved I said how to do it.

Step-by-step explanation:

You rewrite the division question as a multiplication question by flipping the second fraction over. Next, keep the first number, change the division to multiplication and then flip the second fraction over.

I hope this helps UwU

7 0
3 years ago
7+16y=;1/4 solution or no solution?
Ray Of Light [21]

Answer:

the answer is, Y= -27/64

6 0
3 years ago
If r(x)=2-x^2 and w(x)=x-2, what is the range of (w*r)(x)
horrorfan [7]
First, find the product (w*r)(x):  (w*r)(x) = (x-2)*[2-x^2] = 2x - x^3 - 4 + 2x^2

This is a cubing function.  Since the sign of the cube-of-x term is negative, the graph will begin in Quadrant II and pass through Quadrant IV.  There are no limits on y.  Thus, the range is (-infinity, +infinity).

5 0
4 years ago
Read 2 more answers
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