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notsponge [240]
3 years ago
14

How do you name the median of this triangle?​

Mathematics
1 answer:
jarptica [38.1K]3 years ago
5 0

Answer:

F

Step-by-step explanation:

The median is always the letter in the middle

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Find the area of the figure<br> 40 yd<br> 36 yd<br> 20 yd<br> 10 yd<br> 10 yd
Ksenya-84 [330]

Answer:

1640yd

Step-by-step explanation:

10*10*2=200

36*40=1440

200+1440=1640 yd

4 0
3 years ago
Brainliest if correct
natali 33 [55]

\left(15^{1/5} \right)^5  = 15^{(5/5)} = 15^1 = 15

6 0
2 years ago
Im Triggered Pls Dont DELETE!
stepladder [879]

I'm assuming you mean f(x) = (e^x + 5x)^2, not f(x) = (e x + 5x)2, like your prompt suggests.


First, let's figure out what rule we can use. A likely noticeable one is the Power Rule, which says the following:

\dfrac{d}{dx} [u^a] = a(u)^{a-1} du


Applying this, we can solve for the derivative:

f'(x) = 2(e^x + 5x) (e^x + 5)

  • Apply the Power Rule

While you can simplify the expression to your liking, I believe that this form is not overly complex and will thus leave it as is.


Thus, our answer is:

f'(x) = \boxed{2 (e^x + 5x)(e^x + 5)}

7 0
3 years ago
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Who wants some points come and get them
anastassius [24]

Answer:

i want ponts

Step-by-step explanation:

6 0
3 years ago
What is the true solution to the equation below? 2 In e^In2x -In e^In10x = In 30
stealth61 [152]

The\ domain.\\D:x\in\mathbb{R^+}\\\\2\ln e^{\ln2x}-\ln e^{\ln10x}=\ln30\ \ \ |use\ \log_ab^n=n\log_ab\\\\2\ln2x\ln e-\ln10x\ln e=\ln30\ \ \ \ |use\ \log_aa=1\\\\2\ln2x-\ln10x=\ln30\ \ \ |use\ n\log_ab^n=\log_ab^n\\\\\ln(2x)^2-\ln10x=\ln30\\\\\ln4x^2-\ln10x=\ln30\ \ \ |use\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\ln\dfrac{4x^2}{10x}=\ln30\\\\\ln\dfrac{2x}{5}=\ln30\iff\dfrac{2x}{5}=30\ \ \ \ |\cdot5\\\\2x=150\ \ \ \ |:2\\\\x=75\in D

Answer: x = 75

8 0
3 years ago
Read 2 more answers
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