8yards=24ft
as a fraction=3/24
simplest form=1/8
hope this helps
Answer:
24, 14
Step-by-step explanation:
x + y = 38
x = 10 + y
You can substitute (10+y) into the top equation where the x is.
10 + y + y = 38
10 + 2y = 38
2y = 28
y = 14
Now plug 14 in for y in either equation to get x
x = 10 + 14
x = 24
Answer:
Between (-6,0) and (-5,0).
Step-by-step explanation:
When it crosses the x axis, it's an x-intercept. To find the x-intercept, set y (aka f(x)) to zero. The solutions to the equation are approximately 3.36 and - 5.36. Since you're finding the negative x-intercept, you only need the negative solution - 5.36. This is in between (-6,0) and (-5,0).
Answer:
159 m
Step-by-step explanation:
From the information given:
It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.
Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.
Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.
We are to find, the magnitude of the ostrich's eastward component.
i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.
Using the Pythagoras rule:
ES² = OE² + OS²
226² = OE² + 161²
226² - 161² = OE²
OE² = 226² - 161²
OE² = 51076 - 25921
OE² = 51076 - 25921
OE² = 25155
OE = 158.60 m
OE ≅ 159 m
Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.
Answer:
As the sucrose concentration is higher in the solution, the water in the balloon, where the sucrose is less concentrated, will tend to leave and try to dilute the outer solution until both sucrose concentrations are equal. But as the water leaves the balloon, the concentration inside will increase, so it will flow outside until both concentrations are equal and not until the outer concentration is similar to the initial concentration in the balloon.
Step-by-step explanation:
Hope this helps:)
