Based on the data given, I would presume that the data will be 75 percent in the chance of also having an accident.
However, data is still insufficient. Thank you for your question. Please don't hesitate to ask in Brainly your queries.
Answer:
360 in ^3
Step-by-step explanation:
The volume is given by
V = l*w*h
= 8 * 5 * 9
= 360 in ^3
Answer:
Explanation:
You can convert the percent markup into a multiplicative factor in this way:
Base price: 15,800 . . . (cost to the seller)
Percent mark up: 115% . . . (based on the cost to the seller)
Sale price: 15,800 + 115% of x = 15,800 + 115 × 15,800 /100 =
= 15,800 + 1.15 × 15,800 = 15,800 (2.15) = 33,970
The markup is:
- Markup = price paid by the seller - cost to the seller = 33,970 - 15,800 = 18,170 (notice that this is 115% of 15,800)
And <em>the percent markup based on the sale price is</em>:
- % = (markup / sale price) × 100 = (18,700 / 33,970) × 100 =
= 53.49 %
Rounding to the nearest tenth percent that is 53.5 %.
Answer: Jack
Step-by-step explanation:
100÷2=50
50÷23=2.1739130435
50÷18=2.7777.....8
The given expression is ![3b^2*(\sqrt[3]{54a}) + 3*(\sqrt[3]{2ab^6})](https://tex.z-dn.net/?f=%203b%5E2%2A%28%5Csqrt%5B3%5D%7B54a%7D%29%20%2B%203%2A%28%5Csqrt%5B3%5D%7B2ab%5E6%7D%29%20)
This can be simplified as :
= ![3*b^2*(\sqrt[3]{27 *2*a}) + 3*(\sqrt[3]{2*a*b^6})](https://tex.z-dn.net/?f=%203%2Ab%5E2%2A%28%5Csqrt%5B3%5D%7B27%20%2A2%2Aa%7D%29%20%2B%203%2A%28%5Csqrt%5B3%5D%7B2%2Aa%2Ab%5E6%7D%29%20)
We know that: ![\sqrt[3]{27} = 3](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27%7D%20%20%3D%203%20%20%20)
Similarly we also can simplify: ![\sqrt[3]{b^6} = b^2](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B3%5D%7Bb%5E6%7D%20%20%3D%20b%5E2%20)
So our expression will look like this:
= ![3*3*b^2*(\sqrt[3]{2a}) + 3*b^2*(\sqrt[3]{2a})](https://tex.z-dn.net/?f=%203%2A3%2Ab%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20%2B%203%2Ab%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20)
= ![9b^2*(\sqrt[3]{2a}) + 3b^2*(\sqrt[3]{2a})](https://tex.z-dn.net/?f=%209b%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20%2B%203b%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20)
=![\sqrt[3]{2a}*(9b^2 + 3b^2)](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B3%5D%7B2a%7D%2A%289b%5E2%20%2B%203b%5E2%29%20)
=![\sqrt[3]{2a}*(12b^2)](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2a%7D%2A%2812b%5E2%29%20)
This can also be written as:
![12b^2(\sqrt[3]{2a})](https://tex.z-dn.net/?f=%2012b%5E2%28%5Csqrt%5B3%5D%7B2a%7D%29%20)
So the Answer is Option B