Answer:
Step-by-step explanation:
The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:
--------------------(i)
From the question,
the point is (5, 0, -6)
the plane is x + y + z = 6
Therefore,
a = 5
b = 0
c = -6
m = 1
n = 1
t = 1
r = 6
Substitute these values into equation (i) as follows;
Therefore, the shortest distance from the point to the plane is
Answer:
z = 10
Step-by-step explanation:
the steps have been attached above
this is the answer, its pretty simple. I'm not sure the mathematical procedures but if you plug in 7 you get 49. Then all you got to do is subtract by 7, because the question states the number is the same. So basically,
2/3=x/12
Use cross multiply
2*12=3*x
24=3x
Divided both side by 3
24/3=3x/3
x=8
Check:
2/3=x/12
Substitute x with 8
2/3=8/12
2/3=(8/4)/(12/4)
2/3=2/3. As a result, x=8. Hope it help!
