All categories

2 years ago

Find sin theta if cos theta is 4/5

Mathematics

1 answer:

Dima020 [189]2 years ago

5 0

Answer:

Step-by-step explanation:

hello :

cos²θ +sin²θ = 1 and cosθ =4/5

(4/5)² + sin²θ = 1 so : sin²θ = 1 - 16/25

sin²θ = 9/25 = (3/5)²

sinθ = 3/5 or sinθ = - 3/5 because : (3/5)²= (- 3/5)²= 9/25

You might be interested in

On average and adult rest of it breathes in and out 12 times per minute about how many breaths will an adult take in a day?

Firlakuza [10]

Ques 1: 1min->12 breathsl
24*60=1440->12*24*60=17280breaths
answer : 17280 breaths
ques 2: 2 weeks(6*2=12days) -> 2808
1 day->2808/12=234 miles
answer :234 miles

8 0

2 years ago

G (x)=x-3 and h(x)= square root of x, find(g o h) (25)

nevsk [136]

H(25) = sqrt25 = 5

g(5) = 5 - 3 = 2

answer is 2

7 0

2 years ago

A car traveling east at 40.0 m/s passes a trooper hiding at the roadside. The driver uniformly reduces his speed to 25.0 m/s in

Anni [7]

Step-by-step explanation:

It is given that,

Initial speed of the car, u = 40 m/s

Final speed of the car, v = 25 m/s

Time taken, t = 3.5 s

(a) We need to find the magnitude and direction of the car’s acceleration as it slows down. It can be calculated using formula as :

$a=\dfrac{v-u}{t}$

$a=\dfrac{25-40}{3.5}$

$a=-4.28\ m/s^2$

The acceleration is in the opposite direction of motion i.e. west.

(b) Let s is the distance the car travel in the 3.5-s time period. It can be calculated using the third equation of motion as

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{25^2-40^2}{2\times (-4.28)}$

s = 113.9 meters

Hence, this is the required solution.

6 0

2 years ago

The midpoint of AB is M(-1, -2)M(−1,−2). If the coordinates of AA are (1, 3)(1,3), what are the coordinates of BB?

Sholpan [36]

of the quotient of the rectangular prism of green green and green green yellow green eeewww

4 0

2 years ago

Determine the first four terms of the sequence in which the nth term is...

Anon25 [30]

Answer:

1/5, 1/6, 1/7, 1/8

Step-by-step explanation:

The formula for the sequence is (n+3)!/ (n+4)!

The first terms uses n=1

a1 = (1+3)!/ (1+4)! = 4!/5! = (4*3*2*1)/(5*4*3*2*1) = 1/5

The first terms uses n=2

a2 = (2+3)!/ (2+4)! = 5!/6! = (5*4*3*2*1)/(6*5*4*3*2*1) = 1/6

The first terms uses n=3

a3 = (3+3)!/ (3+4)! = 6!/7! = (6*5*4*3*2*1)/(7*6*5*4*3*2*1) = 1/7

The first terms uses n=4

a4 = (4+3)!/ (4+4)! = 7!/8! = (7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1) = 1/8

7 0

2 years ago

Read 2 more answers