Answer:
Yes.
From Definition - A special relationship where each input has a single output.
Check if there is going to be one y for one x.
Step-by-step explanation:
- Re-write it in terms of y=…., meaning solve for y
- If it looks like you have two equations then it is a relationship -case a
- If you need to prove that one has a function for case b, you would point out that if you substitute any value you will get some value in Reals.
100 notes were altogether
<em><u>Solution:</u></em>
Given that ratio of the number of $2 notes to the number of $5 notes was 4 : 1
number of $2 notes : number of $5 notes = 4 : 1
Let 4x be the number of $ 2 notes
Let 1x be the number of $ 5 notes
Given that total value of notes is $ 260
Therefore,
$ 2 (number of $ 2 notes ) + $ 5(number of $ 5 notes ) = $ 260
$ 2(4x) + $ 5(1x) = $ 260
8x + 5x = 260
13x = 260
x = 20
<em><u>Thus number of notes altogether is given as:</u></em>
4x + 1x = 4(20) + 1(20) = 80 + 20 = 100
Thus 100 notes were altogether
80 is a good one to start with.
After that, you can move on to 83, 481, 1687, and 102,974,589 .
Add those together is 7/10
