Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or 
ft
= 
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
= 
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k()
k = 18
Work done (W) to stretch the spring by ft will be
W = 
= 
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9()²
= 7.56 lb-ft
Answer:
£21552.
Step-by-step explanation:
Given information:
Principal amount = £18790
Rate of simple interest =4.9% = 0.049 per year
Time = 3 years
Formula for simple interest:
where, P is principal, r is rate of interest and t is time in years.
Total amount after 3 year is
Therefore, Dan have £21552 after 3 years.
Lizzy's new neckalce cost 0.4 cents less than lucy's neckalce that cost 0.29. cents.How many cents did lizzy's neckalce cost.
The expression can be simplified as:
b-8
