Question

What is the volume, in liters, of a 0.2 M solution containing 8.5 grams of AgNO3?

Answer 1

Answer:

The volume of a 0.2 M solution containing 8.5 grams of AgNO₃ is 0.25 L

Explanation:

 Molarity (M) is a common way of expressing the concentration of solutions. It is defined as the number of moles of solute per volume of solution. The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution.

$Molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$.

Being the molar mass of AgNO3 169.87 g / mol, then you can apply the following rule of three: if 169.87 grams are present in 1 mole of the compound, 8.5 grams will be present in how many moles?

$amount of moles=\frac{8.5 grams*1 mole}{169.87 grams}$

amount of moles= 0.05

So, being the molarity equal to 0.2 M, replacing in the definition of molarity:

$0.2 M=\frac{0.05 moles}{volume}$

and solving you get:

$volume=\frac{0.05 moles}{0.2 M}$

volume=0.25 L

The volume of a 0.2 M solution containing 8.5 grams of AgNO₃ is 0.25 L