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kogti [31]
3 years ago
12

Why is melting a physical property of the wax, but flammability is a chemical property?

Chemistry
1 answer:
Fiesta28 [93]3 years ago
6 0
Melting is a physical property and a physical change to wax. We know this because although the wax might melt, it will resolidify into its original form. Flammability, however, is a chemical change because the act of burning involves a chemical reaction between the gases in the air and heat, which cannot be reversed.
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Why is the metric system the preferred system of measurement for science
Nikolay [14]
In is a lot easier because it uses 10s.
3 0
3 years ago
Read 2 more answers
A certain liquid X has a normal boiling point of 108.30 °C and a boiling point elevation constant Kb=1.07 °C kg/mol. A solution
Fynjy0 [20]

Answer:

34,6g of (NH₄)₂SO₄

Explanation:

The boiling-point elevation describes the phenomenon in which the boiling point of a liquid increases with the addition of a compound. The formula is:

ΔT = kb×m

Where ΔT is Tsolution - T solvent; kb is ebullioscopic constant and m is molality of ions in solution.

For the problem:

ΔT = 109,7°C-108,3°C = 1,4°C

kb = 1.07 °C kg/mol

Solving:

m = 1,31 mol/kg

As mass of X = 600g = 0,600kg:

1,31mol/kg×0,600kg = 0,785 moles of ions. As (NH₄)₂SO₄ has three ions:

0,785 moles of ions×\frac{1(NH_{4})_{2}SO_{4}}{3Ions} = 0,262 moles of (NH₄)₂SO₄

As molar mass of (NH₄)₂SO₄ is 132,14g/mol:

0,262 moles of (NH₄)₂SO₄×\frac{132,14g}{1mol} = <em>34,6g of (NH₄)₂SO₄</em>

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I hope it helps!

7 0
3 years ago
What is the total number of atoms in this formula?<br> NaHCO3
Pavel [41]
6 - one sodium atom, 1 hydrogen atom, 1 carbon atom, and 3 oxygen atoms.


7 0
3 years ago
Calculate the Ph of:
andrey2020 [161]

Answer:

pH= 3.82

Explanation:

Sodium ethanoate or sodium acetate (CH3COONa) ionises completely.

Ethanoic acid or acetic acid (CH3COOH), ionises partially because it is a weak acid.

4 0
3 years ago
3. A compound consists of 91.63 grams of carbon, 7.69 grams of hydrogen and 40.81 grams of
Vikentia [17]

Answer:

Molecular formula = C₁₂H₁₂O₄

Empirical formula is C₃H₃O.

Explanation:

Given data:

Mass of C = 91.63 g

Mass of H = 7.69 g

Mass pf O = 40.81 g

Molar mass of compound = 220 g/mol

Empirical formula = ?

Molecular formula = ?

Solution:

Number of gram atoms of H = 7.69 / 1.01 = 7.61

Number of gram atoms of O = 40.81 / 16 = 2.55

Number of gram atoms of C = 91.63 / 12 = 7.64

Atomic ratio:

            C                      :      H                :         O

           7.64/2.55          :    7.61 /2.55    :       2.55/2.55

               3                     :          3               :        1

C : H : O = 3 : 3 : 1

Empirical formula is C₃H₃O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass  = 3×12+ 3×1.01 +16 = 55.03

n = 220 / 55.03

n = 4

Molecular formula = 4 (empirical formula)

Molecular formula = 4 (C₃H₃O)

Molecular formula = C₁₂H₁₂O₄

8 0
3 years ago
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