Which member of each pair of compounds forms intermolecular H bonds? Draw the H-bonded structures in each case:
1 answer:
FCH₂CH₂F will form Intermolecular Hydrogen bond
FCH₂CH₂F has H-F atoms linked together by Hydrogen bond whereas in HOCH₂CH₂OH here, carbon is linked with oxygen and oxygen is again linked with Hydrogen.
<h3>What is Intermolecular Hydrogen bond ?</h3>Intermolecular hydrogen bonding refers to the formation of hydrogen bonds between molecules of the same or distinct substances. As an illustration, consider hydrogen bonds in water, alcohol, ammonia, etc.
- An illustration. (i) hydrogen connection between the hydrogen fluoride molecules. (ii) The hydrogen bond in molecules of alcohol or water
- Atoms within a molecule are held together by intramolecular forces. There are forces between molecules known as intermolecular forces.
Learn more about Hydrogen bond here:
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Answer:
Reasonable Second step-
Explanation:
The given single step chemical reaction is as follows.
Suppose a two-step mechanism is proposed for this reaction,
The reaction occured in two steps they are as follows.
<u>First of all, what is electrolysis?</u>
Electrolysis is the process of breaking down ionic substances using direct current.
<u>Important points about electrolysis </u>
→ Ionic substances contain particles called ions.
→ Electricity is the flow of electrons or ions. For electrolysis to work, the compound must contain ions. The ions must be free to move for electrolysis to occur and it can happen by melting or dissolving an ionic substance in water.
→ Positively charged ions move to the negative electrode. They receive electrons and are <em>reduced</em>. The positive ions move towards the negative electrode because they want to cancel each other out.
→ Negatively charged ions move to the positive electrode. They lose electrons and are <em>oxidised</em>. The substance that is broken down is called the electrolyte <em>(an electrolyte is just a liquid or solution that can conduct electricity)</em> . The negative ions move towards the positive electrode because they want to cancel each other out.
<h3>Cathode = Negative electrode</h3><h3>Anode = Positive electrode</h3>Metal ions form at the cathode and non-metal ions form at the anode
How I remember if an element is <em>oxidised</em> or <em>reduced</em> is by remembering OIL RIG
OIL = Oxidation is Loss (of electrons)
RIG = Reduction is Gain (of electrons)
<h2><em><u>The answer to your question</u></em></h2>1) The first step would be to clean the metal ring and sand it down because when the metal atoms from the electrolyte are deposited onto the ring, they will form a weak bond and they may simply 'fall' off. Also this could affect conductivity and the whole experiment. The more things you do accurately now, the more accurate your result will be.
2) You want to put the solution you are given in to the tank your going to be using.
3) This is basically the main part, you want to set up the circuit, I have attached a diagram at the bottom to show you the circuit. The copper rod will be the anode and the metal ring will be a cathode (ignore the elements).
4) Now turn on the circuit and you will start to see the solution spilt with the the solution now being split some going to the anode and some going the cathode.
5) Then a thin layer should form on the electrode.
Hope this helps :)
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