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AURORKA [14]
3 years ago
5

Based on the following thermodynamic data, calculate the boiling point of ethanol in degrees Celsius. Substance ΔH∘f (kJ/mol) S∘

f [J/(K⋅mol)] C2H5OH(l) −277.7 160.6 C2H5OH(g) −235.1 282.6 Express the boiling point numerically in degrees Celsius.
Chemistry
1 answer:
levacccp [35]3 years ago
8 0

Answer:

76.03 °C.

Explanation:

Equation:

C2H5OH(l) --> C2H5OH(g)

ΔHvaporization = ΔH(products) - ΔH (reactants)

= (-235.1 kJ/mol) - (-277.7 kK/mol)

= 42.6 kJ/mol.

ΔSvaporization = ΔS(products) - ΔS(reactants)

= 282.6 J/K.mol - 160.6 J/K.mol

= 122 J/K.mol

= 0.122 kJ/K.mol

Using gibbs free energy equation,

ΔG = ΔH - TΔS

ΔG = 0,

T = ΔH/ΔS

T = 42.6/0.122

= 349.18 K.

Coverting Kelvin to °C,

= 349.18 - 273.15

= 76.03 °C.

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(a)Determine the number of KNO3 molecules in 0.750 mol KNO3.
svp [43]

A. The number of molecules in 0.750 mole of KNO₃ is 4.515×10²³ molecules

B. The mass (in milligrams) of 2.39×10²⁰ molecules of Ag₂SO₄ is 124 mg

C. The number of molecules in 3.429 g of NaHCO₂ is 3.04×10²² molecules

<h3>Avogadro's hypothesis </h3>

1 mole of substance = 6.02×10²³ molecules

<h3>A. How to determine the number of molecules </h3>

1 mole of KNO₃ = 6.02×10²³ molecules

Therefore,

0.750 mole of KNO₃ = 0.75 × 6.02×10²³

0.750 mole of KNO₃ = 4.515×10²³ molecules

<h3>B. How to determine the mass of Ag₂SO₄</h3>

6.02×10²³ molecules = 312 g of Ag₂SO₄

Therefore,

2.39×10²⁰ molecules = (2.39×10²⁰ × 312) / 6.02×10²³

2.39×10²⁰ molecules = 0.124 g

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2.39×10²⁰ molecules = 0.124 g × 1000

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<h3>C. How to determine the number of molecules </h3>

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Therefore,

3.429 g of NaHCO₂ = (3.429 × 6.02×10²³) / 68

3.429 g of NaHCO₂ = 3.04×10²² molecules

Learn more about Avogadro's number:

brainly.com/question/26141731

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Why is the value of ea for a spontaneous reaction less than the ea value for the same reaction running in reverse?
Vsevolod [243]

Answer and Explanation:

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  • Spontaneous reactions are mainly exothermic reactions and are represented on the energy profile diagram as shown in <em>the attached image.</em>
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As the spontaneous reaction (exothermic), the energy of the products is lower than that of the reactants.

The difference in energy between reactants and products is the enthalpy change of the reaction (ΔH).

The activation energy (Ea) of the forward direction is the difference between  the energy of the the activated complex state and the reactants state.

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In the reverse direction we need a supply of energy because the reaction is converting from a more stable state (low energy) to a lower stable state (high energy).

The supply in the reverse direction is ΔH, the amount of heat released in the forward direction.

Here, the activation energy of the reverse direction will be <em>(Ea of the forward direction + ΔH)</em>.

The difference between the Ea of the reverse and forward direction is ΔH.

Ea reverse = Ea forward + ΔH.

<em>So, in spontaneous reactions, the value of the Ea of forward direction is lower than the same reaction running in the reverse direction.</em>

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