1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dalvyx [7]
3 years ago
14

This question is related to linked-list representation of disjoint sets. Consider two sets Sx and Sy that have 3 and 5 elements,

respectively. A union (UNION(x,y)) of the sets Sx and Sy represented by x and y, respectively will perform _________________ update(s) of the attribute .next.
Computers and Technology
1 answer:
sattari [20]3 years ago
8 0

Answer:

A union (UNION(x,y)) of the sets Sx and Sy represented by x and y, respectively will perform ________4_________ update(s) of the attribute.

Explanation:

The UNION (x, y) disjoint-set data structure unites the dynamic sets that contain x and y, say Sx and Sy, into a new set.  It is called the union of the two sets. Before the union operation, the two sets are disjoint.  After the union operation, the representative of the resulting set is some member of Sx and Sy or either Sx or Sy. The sets Sx and Sy are then destroyed to remove them from the union collection S.  So, four operations are required.

You might be interested in
When performing the ipconfig command, what does the following output line depict if found in the tunnel adapter settings?
Andrew [12]

Answer:

d. IPv4 Address 192.168.0.4 is associated with the globe IPv6 address 2001:db8:0:10:0:efe

Explanation:

The adapter setting will be associated with the global IP address. When Ipconfig command is operate the IP address finds the relevant domain and then address will use a different subnet. The network will use both IPv4 and IPv6 subnets in order to execute the command.

8 0
3 years ago
Jennifer has written a business report. What should be her last step before she submits the story for publication?
Montano1993 [528]
Revising and editing because it makes the report look sharp and business like.
5 0
4 years ago
Read 2 more answers
A common fallacy is to use MIPS (millions of instructions per second) to compare the performance of two different processors, an
yulyashka [42]

The question is incomplete. It can be found in search engines. However, kindly find the complete question below:

Question

Cites as a pitfall the utilization of a subset of the performance equation as a performance metric. To illustrate this, consider the following two processors. P1 has a clock rate of 4 GHz, average CPI of 0.9, and requires the execution of 5.0E9 instructions. P2 has a clock rate of 3 GHz, an average CPI of 0.75, and requires the execution of 1.0E9 instructions. 1. One usual fallacy is to consider the computer with the largest clock rate as having the largest performance. Check if this is true for P1 and P2. 2. Another fallacy is to consider that the processor executing the largest number of instructions will need a larger CPU time. Considering that processor P1 is executing a sequence of 1.0E9 instructions and that the CPI of processors P1 and P2 do not change, determine the number of instructions that P2 can execute in the same time that P1 needs to execute 1.0E9 instructions. 3. A common fallacy is to use MIPS (millions of instructions per second) to compare the performance of two different processors, and consider that the processor with the largest MIPS has the largest performance. Check if this is true for P1 and P2. 4. Another common performance figure is MFLOPS (millions of floating-point operations per second), defined as MFLOPS = No. FP operations / (execution time x 1E6) but this figure has the same problems as MIPS. Assume that 40% of the instructions executed on both P1 and P2 are floating-point instructions. Find the MFLOPS figures for the programs.

Answer:

(1) We will use the formula:

                                       CPU time = number of instructions x CPI / Clock rate

So, using the 1 Ghz = 10⁹ Hz, we get that

CPU time₁ = 5 x 10⁹ x 0.9 / 4 Gh

                    = 4.5 x 10⁹ / 4 x 10⁹Hz = 1.125 s

and,

CPU time₂ = 1 x  10⁹ x 0.75 / 3 Ghz

                  = 0.75 x 10⁹ / 3 x 10⁹ Hz = 0.25 s

So, P2 is actually a lot faster than P1 since CPU₂ is less than CPU₁

(2)

     Find the CPU time of P1 using (*)

CPU time₁ = 10⁹ x 0.9 / 4 Ghz

                = 0.9 x 10⁹ / 4 x 10⁹ Hz = 0.225 s

So, we need to find the number of instructions₂ such that  CPU time₂ = 0.225 s. This means that using (*) along with clock rate₂ = 3 Ghz and CPI₂ = 0.75

Therefore,   numbers of instruction₂ x 0.75 / 3 Ghz = 0.225 s

Hence, numbers of instructions₂ = 0.225 x 3 x  10⁹ / 0.75  = 9 x 10⁸

So, P1 can process more instructions than P2 in the same period of time.

(3)

We recall  that:

MIPS = Clock rate / CPI X 10⁶

  So, MIPS₁ = 4GHZ / 0.9 X 10⁶ = 4 X 10⁹HZ / 0.9 X 10⁶ = 4444

        MIPS₂ = 3GHZ / 0.75 X 10⁶ = 3 x 10⁹ / 0.75 X 10⁶ = 4000

So, P1 has the bigger MIPS

(4)

  We now recall that:

MFLOPS = FLOPS Instructions / time x 10⁶

              = 0.4 x instructions / time x 10⁶ = 0.4 MIPS

Therefore,

                  MFLOPS₁ = 1777.6

                  MFLOPS₂ = 1600

Again, P1 has the bigger MFLOPS

3 0
3 years ago
Int [] val = { 3, 10, 44 };
Shtirlitz [24]

Answer:

4) 3 11 44

Explanation:

Given data

int [] val = { 3, 10, 44 };

The total number of parameters of given array are 3, so total length of array is also 3.

The indexing of array starts with '0', Therefore the indexes of array with length zero are: {0,1,2}

The value of array at index 0 is = 3

similarly,

value at index 1 = 10

value at index 2 = 44

Here, Int i = 1 is storing the value '1' in integer variable i.

In addition to that, any value of index 'i' of an array is selected using array[i].

Therefore,

val[i] is selecting the value of array located at index '1' because i = 1.

val[i] = val[1] = 10

val[i]+1 is selecting the value of array located at index 'i' that is (1) and adding 1 to it

=> val[i] = 10

=> val[i]+1 = 10+1 = 11

Finally,

val[i] = val[i]+1; is copying the val[i]+1 = 11 to value placed at index 1 (10). Hence, the output would be {3 11 44}. So 4th option is correct.

6 0
3 years ago
On an unweighted scale, a grade of A is worth _____ points
Lubov Fominskaja [6]
On an unweighted scale, a grade of A is worth 4 points and  B. 3 points, C. 2 points, and D 1 point. E. 0 points. If you're trying to calculate your gpa then simply add all of those together! BAM                                                                                 
7 0
4 years ago
Other questions:
  • What types of data are commonly entered into a cell ?
    7·2 answers
  • A pointing device uses light to determine hand motion.
    14·1 answer
  • What does "Forward" in emails do?​
    7·1 answer
  • Write a program that prompts the user to enter a string (may contain spaces) and displays its last character. Enter s string: Pr
    13·1 answer
  • Search engine ranking evaluates the variables that search engines use to determine where a URL appears on the list of search res
    7·1 answer
  • Read the following example cover letter:
    7·2 answers
  • Which of the following statements is TRUE of the information systems (IS) department? A. The operations group monitors user expe
    8·1 answer
  • PLEASE HELP!! WILL MARK BRAINLIEST!!
    9·1 answer
  • What font family is Times New Roman an what font family is Arial?
    9·2 answers
  • A program that will ring a bell six times is what kind of program?
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!