Psisiskkkemdnekskdmsmsndndksskdkskd
xnsjnsnajsjanaansnsnw
mm
therefore, kdjsjswnnandnskjswks
answer: eiwjdnwnsncmsjdx
Solve for x by simplifying both sides of the equation, then isolating the variable.
Exact Form would be or look like
x=9/5, -3/5
Answer:
a) The equation is:
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
b) The 98% confidence interval = (5.62784, 6.37216)
Step-by-step explanation:
a. Write down the equation you should use to construct the confidence interval for the average number of days absent per term for all the children. (10 points)
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
b. Determine a 98% confidence interval estimate for the average number of days absent per term for all the children. (10 points)
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
Mean = 6 days
Standard deviation = 1.6 days
Number of samples = 100
Z score of 98% confidence interval = 2.326
Confidence interval = 6 ± 2.326 × 1.6/√100
= 6 ± 2.326 × 1.6/10
= 6 ± 0.37216
= 6 - 0.37216
= 5.62784
6 + 0.37216
= 6.37216
Therefore, the 98% confidence interval = (5.62784, 6.37216)
There are two possible answers: 72 and 90.
We can find the answer by looking at the largest number among the three of them: 18. The only multiples of 18 between 61 and 107 are 72 and 90. We can check that both numbers are also multiples of 6 and 9:
90 : 6 = 15
90 : 9 = 10
72 : 6 = 12
72 : 9 = 8
It would equal 1. you need to do pemdas. so first thing add 1+2= 3. next multiply 3 times 2. Lastly divide 6 by 6 which equals 1