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svp [43]
3 years ago
9

3(4c + 5) = (3.4c) + (3.5) is an example of which property

Mathematics
1 answer:
cestrela7 [59]3 years ago
7 0

Answer: B) Distributive property

Step-by-step explanation:

Definition:

- Commutative property: a+b=b+a

- Distributive property: a(b+c)=ab+ac

- Inverse operation property:

  • In Addition: a+(-a)=0
  • In Multiplication: a×(1/a)=1

- Multiplication property: If a=b, a×c=b×c

Solve:

GIven

3(4c+5)=(3·4c)+(3·5)

This is distributive property because it is distributing 3 to each of the numbers in the parenthesis.

Hope this helps!! :)

Please let me know if you have any quesitons

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The scores on the GMAT entrance exam at an MBA program in the Central Valley of California are normally distributed with a mean
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Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 591, \sigma = 42

What is the probability that a randomly selected application will report a GMAT score of less than 600?

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 591}{42}

Z = 0.21

Z = 0.21 has a pvalue of 0.5832

58.32% probability that a randomly selected application will report a GMAT score of less than 600

What is the probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{50}} = 5.94

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{5.94}

Z = 1.515

Z = 1.515 has a pvalue of 0.9351

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

What is the probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{100}} = 4.2

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{4.2}

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Z = 2.14 has a pvalue of 0.9838

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Answer:

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Step-by-step explanation:

we know that

In this problem we have a exponential function of the form

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a is the initial value (y-intercept)

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r is the rate

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