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miv72 [106K]
3 years ago
5

Can someone help me please like please I need to turn it in like in 10 minutes

Mathematics
1 answer:
BartSMP [9]3 years ago
3 0
Ima give you the graph points just put them there it’s (2,3) then (6,6) then (0,-2)
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Solve <br>60000000+63636733-7373 ​
Yuri [45]

Answer:

your answer is 123629360

Step-by-step explanation:

60000000+63636733-7373 =123629360

i hope this helped

have a nice day,

mark brainliest if u like butterflys

7 0
3 years ago
I'd really appreciate it if anyone could help! :)
PSYCHO15rus [73]

C (third graph, the parabola); To find if it is a function or not draw a vertical line on the graph. If the vertical line could never intercept the figure more than once anywhere on the graph then it is a function.

3 0
3 years ago
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PLEASE PLEASE HELP! Find the measure of APB^.
Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

\angle CAT=\angle CBT=90^{\circ}

Since angle BAT is equal to 65°, angle CAB has measure

\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

\angle CBA=\angle CAB=25^{\circ}

The sum of the measures of all interior angles in triangle is always 180°, so

\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}

Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}

8 0
4 years ago
Which of these is correct step in constructing congruent angles?
lapo4ka [179]
Is something missing
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6 0
4 years ago
Find the imaginary solutions to the following quadratic function:
Temka [501]

Answer:

the solutions are these

Step-by-step explanation:

\frac{3}{14}  +  \frac{ \sqrt{159} }{14} i \: and  \\ \: \frac{3}{14}   -  \frac{ \sqrt{159} }{14} i

8 0
3 years ago
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