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4 years ago

What is the lowest level of sound that can be detected by human hearing? 0 Hz 10 Hz 20 Hz 100 Hz

2 answers:

8 0

These choices are not "levels" of sound. They're frequencies of sound.

The lower limit of audible frequency is usually considered to be 20 Hz.
But there are some people with ears that can hear 10 Hz, and others ...
particularly the elderly ... who can't hear anything below 100 Hz.

The question is a rather poor one.

Ad libitum [116K]4 years ago

8 0

For a person with normal hearing, when it comes to pitch the human hearing range starts low at about 20 Hz.

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A Ford Mustang weighs about 3500 pounds, and can accelerate from 0-60 MPH in about 5 seconds. What force is responsible for this

Hunter-Best [27]

We will apply the concepts related to Newton's second law. At the same time we will convert everything to the system of international units.

$m = 3500lb = 1587.57kg$

The values of the velocities are,

$\text{Initial Velocity} = V_i = 0$

$\text{Final Velocity} = V_f = 60mph = 26.822m/s$

We know that the acceleration is equivalent to the change of the speed in a certain time therefore

$a = \frac{v_f-v_i}{t}$

$a = \frac{26.822-0}{5}$

$a = 5.36m/s^2$

Now applying the Newton's second law we have,

$F= ma$

$F = (1587.57)(5.36)$

$F = 8516.36N$

Therefore the approximate magnitude is 8516.36N

5 0

4 years ago

Calculate the work done in moving a charge of 2 coulombs across 2 points having a potential difference of 12 volts

Veseljchak [2.6K]

Answer:

Work is done in moving a charge of 2 coulomb across two points having a potential difference of 12 volt is 24 joule .

Explanation:

8 0

3 years ago

Difference between incident ray and refracted ray

natima [27]

Answer:

** incident ray.

Incident ray - the ray of light falling on the surface AB is called the incident ray

reflected ray.

** Reflected ray - the incident ray bouncing back in the same medium after striking the reflecting surface is called reflected ray.

3 0

3 years ago

Deduce the relation between kwh and joule define 1 watt

dimulka [17.4K]

Explanation:

We know that kWh is a commercial unit of energy.

Also, 1 Joule = 1 watt × 1 seconds

$1\ kWh=1kW \times 1\ h$

Since ,1 h = 3600 s and 1kW = 1000 W

$1\ kWh=1000\ W \times 3600\ s\\\\1\ kWh = 36\times 10^5\ W-s\\\\1\ kWh=36\times 10^5\ J$

So, the relation is : $1\ kWh=36\times 10^5\ J$

1 watt is defined as the power of an appliance when the energy is transferred at a rate of 1 Joule per second.

5 0

3 years ago

A rocket initially at rest accelerates at a rate of 99.0 meters/second2. Calculate the distance covered by the rocket if it atta

Jobisdone [24]

Answer: The correct answer is option b.

Explanation: We are given that the rocket is at rest initially final velocity is 445m/s.

The acceleration of the rocket is $99.0m/s^2$

To calculate the distance of rocket, we use third equation of motion, which is:

$v^2-u^2=2as$

where, v = final velocity = 445m/s

u = initial velocity = 0m/s

a = acceleration = $99m/s^2$

s = distance = ? m

Putting values in above equation, we get:

$(445)^2-(0)^2=2(99)s\\\\s=1\times 10^3meters$

3 0

3 years ago