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netineya [11]
3 years ago
5

(x+y,y+3)=(6,2y) find the value of x and y​

Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0

Step-by-step explanation:

Solution:

Given:-

(X+y,y+3)=(6,2y)

Equating corresponding elements,we get,

X+y=6------(1)

y+3=2y-----(2)

solving equation (2),

y-2y=-3

-y=-3

y=3.

Now, substituting y=3 in equation (1)

X+3=6

X=6-3

X=3

Therefore,. (X,Y) = (3,3)

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Tike Television has six minutes of advertising space every 15 minutes. How many
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6

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If each commerical is a minuets and they have six minuets than they can fit six commericals.

8 0
3 years ago
4 3/10 divided by 3/5
inysia [295]

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7.16

Step-by-step explanation:

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3 years ago
Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract
anyanavicka [17]

Answer:

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8

Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

\sum\limits_{n = 0}^{\infty} a*r^n you have that

\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}      and that equality is true as long as     |r| < 1.

Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

5 0
3 years ago
What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?
Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = \frac{0.0625}{2} = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

A = πr²

= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125

=3.14 * 0.000976563

= 0.003066406

= 0.00307 (Rounded to 5 decimal places).

Hence, cross-sectional area of a wire is 0.00307 square inches.

Hope this helps you!

5 0
3 years ago
Read 2 more answers
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