Evaluate the logarithm. log 0.00001

Mathematics

1 answer:

Yuki888 [10]3 years ago

4 0

The correct answer is -5.

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Solve the system using elimination<br><br> x + 2y = 1<br> 4x + y = 11

VashaNatasha [74]

X + 2y = 1 ______×1
4x + y = 11 _____ ×2

x + 2y = 1
8x + 2y = 22

8x + 2y = 22
(-)
x + 2y = 1
_____________
7x = 21

x = 3

3 + 2y = 1
2y = 2
y = 1

i am a mathematics teacher. if anything to ask please pm me

3 0

3 years ago

Like b and c are parallel what is the measure of <2

Vadim26 [7]

C
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3 years ago

4y+3y simplify

kykrilka [37]

Answer:

<h2>✓ Simplifying Expressions</h2>

$4y + 3y$

<h3>Solution:</h3>

$4y + 3y \\ = 7y$

Adding the numerical coefficient with the terms that have the same variables. Meaning they are like terms. Adding the base and then copy the variables.

<h3>> Therefore, the answer is 7y.</h3>

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3 years ago

Read 2 more answers

Convert the rectangular coordinates (-9, 3V3) into polar form. Express the angle

Whitepunk [10]

Answer:

$(6\sqrt{3},\,\frac{5\pi}{6})$

Step-by-step explanation:

The radius r can be found from the relationship

$r^2=x^2+y^2\\r^2=(-9)^2+(3\sqrt{3})^2\\r^2=81+27=108\\r=\sqrt{108}\\r=6\sqrt{3}$

The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

$\cos{\theta}=\frac{x}{r}=\frac{-9}{6\sqrt{3}}\\\cos{\theta}=-\frac{9}{6\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}\\\cos{\theta}=-\frac{9\sqrt{3}}{6\cdot3}\\\cos{\theta}=-\frac{\sqrt{3}}{2}\\\\\cos^{-1}\frac{-\sqrt{3}}{2}}=\frac{5\pi}{6}$