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3 years ago

6

I ran 10 miles in 2 hours. What was my average speed?

2 answers:

zaharov [31]3 years ago

7 0

Answer

5

Step-by-step explanation:

gogolik [260]3 years ago

6 0

Answer:

5mph

Step-by-step explanation:

10/2 = 5

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Suppose that a class contains 15 boys and 30 girls, and that 10 students are to be selected at random for a special assignment.

natka813 [3]

Prob of selected students times prob of selecting boys times prob of selecting 3 boys
total students = 15b + 30g = 45 students

1. 10s/45t = 0.22
2. 15b/45t = 0.33
3. 3b/15b = 0.2

0.22×0.33×0.2=0.0148

1.48%

I'm not sure 100%... double check answer please

3 0

3 years ago

Select 3 sides that can form a right triangle.

pochemuha

Answer: 14, 48, 50

Step-by-step explanation:

14^2+48^2=50^2

8 0

2 years ago

A roof rises 24 feet vertically and 14 feet horizontally. What is the slope of the roof?

mixas84 [53]

Answer:

1.714 feet

Step-by-step explanation:

slope is rise over run.

rise would be the vertical measurement and run would be the horizontal measurement.

24/14 = 12/7

12/7 = 1.714

4 0

1 year ago

2x -2=10 solve for x

Aleonysh [2.5K]

Answer:

x=6

Step-by-step explanation:

Take -2 and add it to 10 and get 12. So then the equation is 2x=12. Divide 2 by 12 and get x=6.

8 0

3 years ago

Find an explicit solution to the Bernoulli equation. y'-1/3 y = 1/3 xe^xln(x)y^-2

NNADVOKAT [17]

$y'-\dfrac13y=\dfrac13xe^x\ln x\,y^{-2}$

Divide both sides by $\dfrac13y^{-2}(x)$ :

$3y^2y'-y^3=xe^x\ln x$

Substitute $v(x)=y(x)^3$ , so that $v'(x)=3y(x)^2y'(x)$ .

$v'-v=xe^x\ln x$

Multiply both sides by $e^{-x}$ :

$e^{-x}v'-e^{-x}v=x\ln x$

The left side can be condensed into the derivative of a product.

$(e^{-x}v)'=x\ln x$

Integrate both sides to get

$e^{-x}v=\dfrac12x^2\ln x-\dfrac14x^2+C$

Solve for $v(x)$ :

$v=\dfrac12x^2e^x\ln x-\dfrac14x^2e^x+Ce^x$

Solve for $y(x)$ :

$y^3=\dfrac12x^2e^x\ln x-\dfrac14x^2e^x+Ce^x$

$\implies\boxed{y(x)=\sqrt[3]{\dfrac14x^2e^x(2\ln x-1)+Ce^x}}$

4 0

2 years ago